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JulijaS [17]
3 years ago
10

1-Butanol, 1-butene, and di-n-butyl ether are all removed from the product by washing with concentrated sulfuric acid. Explain w

hy these are removed and why 1-bromobutane is not removed.
Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

1-bromobutane, unlike others, will not be removed because it is an <em>alkane</em> and inert to concentrated sulfuric acid.

Explanation:

<em>Alkanes</em> are saturated organic compounds, primarily made up of hydrogen and carbon atoms. Saturation implies that they posses no double or triple bonds, therefore making them stable and unresponsive to addition reactions and also, concentrated sulfuric acid.

1-Butanol is a primary alcohol. Primary alcohols will react with acids to produce alkyl halides. 1-butene, as an alkene, will react with concentrated sulfuric acid to produce alkyl hyrgensulfate, while di-n-butyl will produce an ether when it reacts with concentrated sulfuric acid.

Therefore, these organic compounds will be washed and converted to other compounds by concentrated sulfuric acid except 1-bromobutane.

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A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. from these data, calculate the density of lead in si units
jeyben [28]
A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is

Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³
4 0
2 years ago
A solution contains an unknown amount of dissolved magnesium. Addition of
Scrat [10]

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

4 0
2 years ago
Answer Quick
kow [346]

Answer:

20.9%

Explanation:

  • The percentage by mass of solution is given by dividing the mass of solute in grams by the mass of solution in grams then multiplying it by 100%.

% Mass of solution = mass of solute/mass of solution × 100%

                               = (27.0 g/ 129.0 g) × 100%

                               = 20.93%

                               = 20.9%

7 0
2 years ago
Read 2 more answers
HOW MANY M ARE IN 3.0X105 MM?
erik [133]

The answer to the question is 300meters.

7 0
3 years ago
Please match the example with the classification of matter in which it belongs. Column A 1. soil: soil 2. chocolate milk: chocol
bekas [8.4K]

Answer:

34

Explanation:

add

8 0
3 years ago
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