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JulijaS [17]
3 years ago
10

1-Butanol, 1-butene, and di-n-butyl ether are all removed from the product by washing with concentrated sulfuric acid. Explain w

hy these are removed and why 1-bromobutane is not removed.
Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

1-bromobutane, unlike others, will not be removed because it is an <em>alkane</em> and inert to concentrated sulfuric acid.

Explanation:

<em>Alkanes</em> are saturated organic compounds, primarily made up of hydrogen and carbon atoms. Saturation implies that they posses no double or triple bonds, therefore making them stable and unresponsive to addition reactions and also, concentrated sulfuric acid.

1-Butanol is a primary alcohol. Primary alcohols will react with acids to produce alkyl halides. 1-butene, as an alkene, will react with concentrated sulfuric acid to produce alkyl hyrgensulfate, while di-n-butyl will produce an ether when it reacts with concentrated sulfuric acid.

Therefore, these organic compounds will be washed and converted to other compounds by concentrated sulfuric acid except 1-bromobutane.

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NEED HELP ASAP!!!
Alexxx [7]

At room temperature oxygen, O_2 is present in the gas phase.

A gas is defined as a substance which is characterized by the rapidly movement of molecules which are widely separated. The shape and volume of gas is not definite that is they take on the shape of the container in which it is placed. The gas molecules have minimum inter-nuclear attractions and thus have high kinetic energy.

Thus, the sentences that describes oxygen at room temperature are:

  • It has no definite volume and takes the shape of its container.
  • Its particles move fast enough to overcome the attraction between them.
  • It has more energy than it would be at a cooler temperature as the kinetic energy is directly proportional to the temperature that is kinetic energy increases on increasing the temperature.

6 0
3 years ago
Assume the average apple has a mass of 167 grams. How many apples are in a bag of apples that weighs 2000 grams? Enter your numb
forsale [732]

Answer:

12

Explanation:

167x=2000

x=11.976

rounds to 12

4 0
2 years ago
The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the
aleksley [76]

Answer:

It will require<u> second round</u> of the cycle to release 14C0_2

Explanation:

<u>Reason behind the requirement of second round of the cycle to release </u>CO_2 -:

The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.

7 0
2 years ago
Which of the following happens during a chemical reaction?
Lana71 [14]
C. atoms of reactants rearrange to form new substances
5 0
3 years ago
Read 2 more answers
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
3 years ago
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