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3 years ago

Example of chemical change?

Chemistry

1 answer:

musickatia [10]3 years ago

3 0

Answer:

Burning of paper and log of wood.

Digestion of food.

Boiling an egg.

Chemical battery usage.

Electroplating a metal.

Baking a cake.

Milk going sour.

Various metabolic reactions that take place in the cells.

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What is the mass of oxygen in 250 go of sulfiric acid, H2CO4

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At 20 degrees Celsius the density of mercury is 13.6 g/cm cubed. What is the mass of 50.0 ml of mercury at 20 degrees Celsius?

Lynna [10]

Answer:

680g of mercury is the mass of the sample of mercury.

Explanation:

Density is an unit used to relates the mass of an object per unit of volume.

For example, in the problem, the density of mercury is 13.6g/cm³, as cm³ is equal to milliliters, mL, the density is: 13.6g/mL.

If you have 50.0mL of mercury, the mass is:

50.0mL * (13.6g / mL) =

<h3>680g of mercury is the mass of the sample of mercury.</h3>

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3 years ago

An _______ bond forms when a cation transfers its extra electron to an anion who needs it.

Nitella [24]

An c.ionic bond forms when a cation transfers its extra electron to an anion who needs it.
For example compound magnesium chloride (MgCl₂) has ionic bond (the electrostatic attraction between oppositely charged ions). Magnesium transfers two electrons (became positive cation) to chlorine (became negative anion).

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3 years ago

Anthony needs to make a solution with a concentration of 2.5m. He begins with 2.0 iters and a 8.0M solution. What final volume d

FrozenT [24]

Answer:

The final volume is 6.4 L.

Explanation:

Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

In this case:

Ci: 8 M
Vi: 2 L
Cf: 2.5 M
Vf: ?

Replacing:

8 M* 2 L= 2.5 M* Vf

Solving:

$Vf=\frac{8 M* 2 L}{2.5 M}$

Vf=6.4 L

The final volume is 6.4 L.

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3 years ago