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arlik [135]
4 years ago
12

A teacher gave his class two quizzes; 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. Det

ermine the percentage of students who passed the first quiz that also passed the second quiz.
Mathematics
2 answers:
bagirrra123 [75]4 years ago
7 0
The percentage of students who passed the first and the second quiz is still 60%. The 80% that passed the first quiz should not be taken into account when determining the answer since the 60% is plainly given.

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.
FromTheMoon [43]4 years ago
5 0

Answer:

The answer is 75%.

Step-by-step explanation:

Let x be the total number of students in the class.

As given - 80% of the class passed the first quiz, so it can be represented as 0.8x

And only 60% of the class passed the second quiz, that is represented as 0.6x

So, to determine the percentage of students who passed the first quiz that also passed the second quiz, we will do the following:

\frac{0.6x}{0.8x}\times100= 75

Therefore, 75% students passed the first quiz and also passed the second quiz.

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Answer:


Step-by-step explanation:

2x^2+8x-12=0

with form

ax^2+bx+c=0


move c to the other side

2x^2+8x=12


x^2 is multiplied -> divide equation by 2

x^2+4x=6


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4*1/2=2


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2^2=4


add 4 to both sides

x^2+4x=6

x^2+4x+4=6+4

x^2+4x+4=10


transform to polynom

(x+2)^2=10


this left side is option B multiplied by a factor of 16 and therefore equal:

(4x + 8)^2

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bonus: calculate root

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<h2 /><h2>so it is option B</h2>
  • <em>2x^2 + 8x - 12 = 0..divide by 2</em>
  • <em>x^2 + 4x - 6 = 0</em>
  • <em>x^2 + 4x = 6...add 4 to both sides of the equation</em>
  • <em>x^2 + 4x + 4 = 6 + 4</em>
  • <em>(x + 2)^2 = 10....<== ur constant is 10</em>
  • <em>x + 2 = (+-)sqrt 10</em>
  • <em>x = -2 (+ - ) sqrt 10</em>
  • <em></em>
  • <em>x = -2 + sqrt 10</em>
  • <em>x = -2 - sqrt 10</em>
  • <em></em>
  • <em></em>
  • <em></em>
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