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Julli [10]
3 years ago
5

What is the molecular formula for C3H2N?

Chemistry
2 answers:
NNADVOKAT [17]3 years ago
5 0
It is empirical formula
nekit [7.7K]3 years ago
5 0
<span><span>C3</span><span>H2</span>N</span> tells you the lowest possible whole number ratio of atoms in that molecule. That EMPIRICAL FORMULA must have the same ratio as the actual, MOLECULAR FORMULA. The empirical mass and molecular mass must share the same ratio as the formulas do, so find the mass of <span><span>C3</span><span>H2</span>N</span>: <span>3(12g)+2(1g)+14g=52g</span> and compare that to the molecular weight of 260g. <span><span><span>MF</span><span>EF</span></span>=<span><span>MW</span><span>EW</span></span></span>so<span><span><span>MF</span><span>EF</span></span>=<span><span>260g</span><span>52g</span></span>=5</span><span>the actual formula is five times heavier than the empirical formula, so take the empirical formula and multiply each subscript by 5. That's why it works</span>
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consider the following equilibrium:h2co3(aq) h2o(l) h3o (aq) hco3-1(aq).what is the correct equilibrium expression?
MAVERICK [17]

The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:<span>

<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>

4 0
3 years ago
If i have an 86 and i don’t do a 50 point assignment, what will my grade be in the class?
nexus9112 [7]
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7 0
3 years ago
Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

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Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

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3 years ago
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Answer:

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3 0
3 years ago
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Answer:

Your answer is A. They will show even dispersion to get water.

Explanation:

3 0
3 years ago
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