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3 years ago

What is the molecular formula for C3H2N?

Chemistry

2 answers:

NNADVOKAT [17]3 years ago

5 0

It is empirical formula

nekit [7.7K]3 years ago

5 0

C3H2N tells you the lowest possible whole number ratio of atoms in that molecule. That EMPIRICAL FORMULA must have the same ratio as the actual, MOLECULAR FORMULA. The empirical mass and molecular mass must share the same ratio as the formulas do, so find the mass of C3H2N: 3(12g)+2(1g)+14g=52g and compare that to the molecular weight of 260g. MFEF=MWEWsoMFEF=260g52g=5the actual formula is five times heavier than the empirical formula, so take the empirical formula and multiply each subscript by 5. That's why it works

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Read 2 more answers

450g of chromium(iii) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS

ExtremeBDS [4]

Answer:

1597.959 g

Explanation:

Given Data:

Amount of Cr₂(SO₄)₃ = 450 g

Amount of potassium phosphate K₃PO₄ = in Excess

grams of potassium sulfate K₂SO₄= ?

Solution

The Reaction will be

Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄

Information that we have from reaction

Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄

1 mol 2 mol 3 mol

we come to know from the above reaction that

1 mole of chromium(iii) sulfate (Cr₂(SO₄)₃) react with 2 mole of potassium phosphate (K₃PO₄) to produce 3 mole of K₂SO₄

We also know that

molar mass of Cr₂(SO₄)₃ = 147 g/mol

molar mass of K₃PO₄ = 212 g/mol

molar mass of K₂SO₄ = 174 g/mol

if we represent mole in grams then

Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄

1 mol (147 g/mol) 2 mol (212 g/mol) 3 mol (174g/mol)

So, Now we have the following details

Cr₂(SO₄)₃ + 2K₃PO₄ ----------> 3K₂SO₄ + 2CrPO₄

147 g 424 g 522 g

So,

we come to know that 147 g of Cr₂(SO₄)₃ combine with 424 g of 2K₃PO₄ produce 522 g of K₂SO₄

So now we calculate that how many grams of potassium sulfate will be produced

Apply unity formula

147 g of Cr₂(SO₄)₃ ≅ 522 g of K₂SO₄

450 g of Cr₂(SO₄)₃ ≅ ? g of K₂SO₄

by doing cross multiplication

g of K₂SO₄ =522 g x 450 g / 147 g

g of K₂SO₄ = 1597.959 g

So the write answer is 1597.959 g

***Note: By calculation it is obvious that the correct answer is 1597.959 g

8 0

3 years ago