Answer:
337.5 g NaCl
Explanation:
.90% saline solution = 90g saline (NaCl)/100mL water (H2O)
1. Use 375 mL to find mass
375 mL × (90 g NaCl/100 mL) = 337.5 g NaCl in 375 mL .9% saline solution
Answer:
deberia ser que tienen que sacar sangre al paciente que tiene el virus a partier de eso se podria ser una pacuna para eliminar el virus
Answer: Substance A will travel further at the end of the experiment and also it will have larger Rf value compared to substance B.
Explanation:
The affinity of substance towards the stationary or mobile phase means how much the substance binds to a phase. Because component B has greater affinity for the stationary phase, it binds more to stationary phase; while component A binds more to a mobile phase. Due to differences in their affinity, component A and B can be separated using chromatography. Stationary phase, as its name says, stays fixed, while the mobile phase is moving. Together with the mobile phase travels component A because of its greater affinity, while component B stays fixed due to its greater affinity for the stationary phase. In conclusion , substance A will travel further at the end of the experiment.
Rf value (Retention Factor) can be defined as the ratio of the distance traveled by a substance in the mobile phase (solute) compared with the distance traveled by the front of the mobile phase itself (solvent front).
Rf = Migration distance of substance / Migration distance of solvent front
Because the solvent front is always larger from the distance traveled by the solute, Rf values are always between 0 and 1. The farther a compound traveled, the larger its Rf value will be. In this example, substance A will have larger Rf value compared to substance B.
Answer:
3.2 × 10³ J
Explanation:
Step 1: Given data
- Mass of the gold ring (m): 25 g
- Specific heat capacity of gold (Cp): 0.129 J/g.°C
- Initial temperature: 75 °C
- Final temperature: 1064 °C
Step 2: Calculate the temperature change (ΔT)
ΔT = 1064 °C - 75 °C = 989 °C
Step 3: Calculate the energy required (Q)
We will use the following expression.
Q = Cp × m × ΔT
Q = 0.129 J/g.°C × 25 g × 989 °C
Q = 3.2 × 10³ J
Explanation:
if 6 grams of copper is used then the product will be increased as well
as the amount of reactant is proportional to amount of product.
we know,
mass number of copper is 63 and the product we found is 158.
now if we have a mathematical explanation...
for (63X2) gm Cu we get 158 gm product
"' 1 gm 158/126 """
""" 4 gm 158X4/126
=5.01 gm
again for 6gm using
for 126 gm we get 158 gm product
""" 1gm 158/126 gm ""
""" 6 gm " ' 158X6/126 gm
=7.52 gm product
SO we can say by comparative study that the product has increased
I THINK THATS THE ANSWER
thank u