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4 years ago

What conditions are necessary for an artesian well

1 answer:

7 0

The geologic<span> conditions necessary for an artesian well are an inclined aquifer sandwiched between impervious </span>rock layers<span> above and below that trap water in it. Water enters the exposed edge of the aquifer at a high </span>elevation<span> and percolates downward through interconnected </span>pore spaces<span>. </span>

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When is an electron in an atom likely to move from one energy level to another

diamong [38]

<h2>Answer:When electrons absorb or emit quantized units of energy in the form of photons.</h2>

Explanation:

When a electron is collided with a photon with exactly the same energy it would require to get to any of the farther orbits,electron transition takes place to an orbit depending on the energy of the photon.

When electrons emit exactly the same amount energy that is difference between the current energy level and the new level,then the electron makes a transition to the new level.

4 0

3 years ago

Read 2 more answers

A coin placed on the cover of a book just begins to move when the cover makes an angle of 38 degrees with the horizontal. What i

RSB [31]

Answer:

m g sin theta = force of object along incline due to gravity

N μ = frictional of incline on object where N is the normal force

N = m g cos theta force perpendicular to incline

m g sin theta = N μ = μ m g cos theta

μ = tan theta = tan 38 = .78

6 0

2 years ago

Part 1

wel

Answer:

Part 1: 0.3789

Part 2: 746 J

Part 3: 2.162 kW

Explanation:

Part 1:

Eff= $1-\frac{1223}{1969}$

Eff= 0.378873 ≈ 0/3789

Part 2:

W= 0.3789(1969)

W= 746 J

Part 3:

$Power=\frac{W}{t}$

$Power= \frac{746}{0.345}$

Power= 2162.3188 Watts

2162.3188 W-----> 2.162 kW

4 0

2 years ago

What parts of an atom determines which element it is?

uysha [10]

Explanation:

The protons determines the atomic number which helps in identifying an atom of an element

4 0

4 years ago

Read 2 more answers

A car of 1000 kg with good tires on a dry road can decelerate (slow down) at a steady rate of about 5.0 m/s2 when braking. If a

vredina [299]

(a) 4.0 s

The acceleration of the car is given by

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time interval

For this car, we have

v = 0 (the final speed is zero since the car comes to a stop)

u = 20 m/s is the initial velocity

$a=-5.0 m/s^2$ is the deceleration of the car

Solving the equation for t, we find the time needed to stop the car:

$t=\frac{v-u}{a}=\frac{0-(20 m/s)}{-5.0 m/s^2}=4 s$

(b) 40 m

The stopping distance of the car can be calculated by using the equation

$v^2 - u^2 = 2ad$

where

v = 0 is the final velocity

u = 20 m/s is the initial velocity

a = -5.0 m/s^2 is the acceleration of the car

d is the stopping distance

Solving the equation for d, we find

$d=\frac{v^2-u^2}{2a}=\frac{0^2-(20 m/s)^2}{2(-5.0 m/s^2)}=40 m$

(c) $-5.0 m/s^2$

The deceleration is given by the problem, and its value is $-5.0 m/s^2$ .

(d) 5000 N

The net force applied on the car is given by

$F=ma$

where

m is the mass of the car

a is the magnitude of the acceleration

For this car, we have

m = 1000 kg is the mass

$a=5.0 m/s^2$ is the magnitude of the acceleration

Solving the formula, we find

$F=(1000 kg)(5.0 m/s^2)=5000 N$

(e) $2.0\cdot 10^5 J$

The work done by the force applied by the car is

$W=Fd$

where

F is the force applied

d is the total distance covered

Here we have

F = 5000 N

d = 40 m (stopping distance)

So, the work done is

$W=(5000 N)(40 m)=2.0\cdot 10^5 J$

(f) The kinetic energy is converted into thermal energy

Explanation:

when the breaks are applied, the wheels stop rotating. The car slows down, as a result of the frictional forces between the brakes and the tires and between the tires and the road. Due to the presence of these frictional forces, the kinetic energy is converted into thermal energy/heat, until the kinetic energy of the car becomes zero (this occurs when the car comes to a stop, when v = 0).

8 0

4 years ago