All categories

3 years ago

Use complete sentences to describe an extra-solar (exo) planet

Physics

2 answers:

Jobisdone [24]3 years ago

5 0

An exo planet is a planet that orbits a stat outside of the solar system.

anyanavicka [17]3 years ago

4 0

The correct answer of this question : The planet outside of our solar system.

EXPLANATION:

The extra-solar planet is the planet which is present beyond our solar system. It is also known as exoplanet.

Just like our solar system planets like the earth,Mars, Jupiter etc, the exoplanet is also a part of another solar system. The planets revolves around their sun i.e other star in different orbits. This star is the centre of their solar system.

Hence, the exact explanation for the exoplanet is the planet situated beyond our solar system, and revolves around any other centrally situated star.

You might be interested in

What feature of the ocean basin is formed when old oceanic crust is forced under continental plates?

Sholpan [36]

Answer:

Mid ocean ridge is formed when old oceanic crust is forced under continental plates.

Explanation:

Ocean basin is a kind of land surface that is present under an ocean and below the water.

Ocean basin contain continental shelf,mid ocean ridge that is found on the sea floor.

The size of ocean basin is equal to the size of an ocean and is found below the ocean.

When, water covers the earth's crust region in the distant past,ocean basin formation occurs.This prcess require long time as spreading of sea floor and tectonic plates takes place.

Ex-Atlantic Ocean basin is formed over million years that is present in the European Continent.

4 0

4 years ago

A student walks 4 blocks east, 1 blocks north, 2 block west and then 1 blocks south in an hour. Her average velocity is?

arsen [322]

Answer:

2 m/s

Explanation:

Given that a student walks 4 blocks east, 1 blocks north, 2 block west and then 1 blocks south in an hour.

The total time = 1 hour

The vertical displacement = 1 - 1

Vertical displacement = 0

Horizontal displacement = 4 - 2

Horizontal displacement = 2

Total displacement = sqrt (2^2 - 0^2)

Total Displacement = 2

Average velocity = displacement/time

average velocity = 2 / 1

Average velocity = 2 m/s

Therefore, her average velocity is 2 metres per second.

4 0

4 years ago

(1 point) At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 22 knots and ship B is sailing nort

Veronika [31]

Answer:28.8 knots

Explanation:

The ships are moving as the sides of a right triangle. Thus, Pyhogorean theorem will be useful in the following steps. Next, we have to know that the rate of change in distance, which is called velocity, can be described in terms of derivatives.

First, we have to calculate the distances covered by the ships from noon to 6 PM. In 6 hours, ship A moved 22*6=132 nautical mile. However, their first distance was 10 nautical miles, so 132+10=142 miles is the equivalent of A's displacement. For B, the distance travelled is 19*6=114 miles. From now on, A=142 miles and B=114 miles.

The distance between them is described with Pythogorean theorem, which is $D=\sqrt{A^{2} +B^{2} }$ and when we replace the values A and D, we find Distance (D) to be 182 miles.

Now, let's make the notations clear. The velocity of A and B is notated as $\frac{dA}{dt}$ and $\frac{dB}{dt}$ . The rate of change of distance is also notated as $\frac{dD}{dt}$ . Now, we have to find $\frac{dD}{dt}$ from the Pythogorean theorem. If we derive the Pythogorean expression $D=\sqrt{A^{2} +B^{2} }$ , we would have:

$\frac{dD}{dt} =\frac{1}{2} *(A^{2} +B^{2} )^{-1/2} *(2*A*\frac{dA}{dt} + 2*B*\frac{dB}{dt} )$

The derivation here includes chain rule and derives the interior parts of the parenthesis. When we insert distances for A and B and velocities for derivation notations, the formula becomes:

$\frac{dC}{dt} =\frac{1}{2}*(142^{2} +114^{2})^{-\frac{1}{2} }*(2*142*22 + 2*114*19)$ and the answer is 28.6 knots.