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svetlana [45]
3 years ago
12

Use complete sentences to describe an extra-solar (exo) planet

Physics
2 answers:
Jobisdone [24]3 years ago
5 0
An exo planet is a planet that orbits a stat outside of the solar system.
anyanavicka [17]3 years ago
4 0

The correct answer of this question : The planet outside of our solar system.

EXPLANATION:

The extra-solar planet is the planet which is present beyond our solar system. It is also known as exoplanet.

Just like our solar system planets like the earth,Mars, Jupiter etc, the exoplanet is also a part of another solar system. The planets revolves around their sun i.e other star in different orbits. This star is the centre of their solar system.

Hence, the exact explanation for the exoplanet is the planet situated beyond our solar system, and revolves around any other centrally situated star.


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How is work and energy inter-related?? (in simple words)​
matrenka [14]

Answer:

The work and energy is inter- related because if we are energetic then only we are able to work.

People who are weak and not energetic cannot work continuously.

Explanation:

hope this helps you....

4 0
2 years ago
A car is accelerating to the right. In which direction is the applied force?
Natasha_Volkova [10]

Answer:

Left

Explanation:

The force is applied opposite of the acceleration.

8 0
3 years ago
Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t square
Dahasolnce [82]

Answer:

a. Time=25seconds

b.distance=1041.67m

Explanation:

a.The equation for D in terms of m/s is \frac{250}{3}m/s after conversion.

To find when speed reaches 300km/hr=83.33m/s, we find D\prime and solve for t

D=\frac{5}{3}t^2\\D\prime=\frac{5}{3}(2t)=\frac{10}{3}t=\frac{250}{3}\\t=25sec

b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.

#To find distance travelled in that time , we substitute fort=25 in our distance equation:

D(25)=\frac{5}{3}(25)^2\\=1041.67m

Hence the distance of the plane before it gets airborne is 1041.67m

4 0
3 years ago
A toy car goes over a small ramp at a horizontal velocity of 1.21 m/s and decelerates at 0.131 m/s2 while in the air. The total
xz_007 [3.2K]
We need to considerate only the horizontal component of the motion of the toy car.

The formula for the distance in a decelerated motion is:
s = s₀ + v₀·t - 1/2·a·t²

where:
s₀ = initial position = 0
v₀ = initial velocity = 1.21 m/s
t = time elapsed = 0.342 s
a = deceleration = 0.131 m/s²

Plugging in numbers:
s = 0 + 1.21×0.342 - 0.5×0.141×(0.342)²
  = 0.406 m

Hence, the toy car traveled a distance of about 41 cm.

3 0
3 years ago
Liquids usually have higher volume coefficients of expansion than solids do. <br> true or false
Ulleksa [173]

Answer: true

Explanation:

5 0
3 years ago
Read 2 more answers
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