Answer:42.4m/s^2
Explanation:
Velocity(v)=6m/s
Radius(r)=0.85 meter
Centripetal acceleration=(v x v) ➗ r
Centripetal acceleration=(6 x 6) ➗ 0.85
Centripetal acceleration=36 ➗ 0.85
Centripetal acceleration=42.4
Answer: 75.02 m
Explanation:
u = 0 ( starts from rest )
v = 50 m/s
t = 3 s
( i ) a = v - u / t
= 50 - 0 /3
= 16.67
( ii ) s = ut + 1/2 at²
= 0 × 3 + 1/2 × 16.67 × 3 × 3
= <u>75.02 m</u>
Hope this helps...
Answer:
The tangential speed of the tack is 8.19 m/s.
Explanation:
The wheel rotates 3.37 times a second that means wheel complete 3.37 revolutions in a second. Therefore, the angular speed ω of the wheel is given as follows:
Use the relation of angular speed with tangential speed to find the tangential speed of the tack.
The tangential speed v of the tack is given by following expression
v = ω r
Here, r is the distance to the tack from axis of rotation.
Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.
v = 21.174 × 0.387
v = 8.19m/s
Thus, The tangential speed of the tack is 8.19 m/s.