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alexandr1967 [171]
3 years ago
7

What type of wave travels faster through solids than it does through gases?

Physics
2 answers:
Ede4ka [16]3 years ago
5 0

Answer:

Liquids are more dense than gases, but less dense than solids, so sound travels 2nd fast in liquids. Gases are the slowest because they are the least dense: the molecules in gases are very far apart, compared with solids and liquids.

Explanation:

Naddik [55]3 years ago
5 0

Answer:

Longitudinal waves travels faster through solids than it does through gases

Explanation:

As we know that longitudinal waves travels through all types of mediums and the speed of longitudinal waves is given as

v = \sqrt{\frac{E}{\rho}}

here we know that

E = elasticity of the medium

\rho = density of the medium

now here we know that elasticity of solids is much more than the elasticity of gases

So the speed of longitudinal waves in solids is more than the speed of waves in gases

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Based on the replacement reaction, what would the products of the reaction be?
cricket20 [7]

Answer:

\rm Be(OH)_2 and \rm (NH_4)_2 SO_4. The missing ion would be \rm OH^{-}.

Explanation:

In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.

In this question, the two ionic compounds are:

  • \rm BeSO_4, and
  • \rm NH_4 OH.

In particular,

  • \rm BeSO_4 is made up of \rm Be^{2+} ions and \rm {SO_4}^{2-} ions, while
  • \rm NH_4 OH is made up of \rm {NH_4}^{+} ions and \rm OH^{-} ions.

In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)

  • \rm Be^{2+} is a cation. In \rm BeSO_4, \rm Be^{2+} was bounded \rm {SO_4}^{2-} anions. During the reaction, it bonds with \rm OH^{-} anions to produce \rm Be(OH)_2.
  • \rm {NH_4}^{+} is also a cation. In \rm NH_4 OH, \rm {NH_4}^{+} was bounded to \rm OH^{-} ions. During the reaction, it bonds with \rm {SO_4}^{2-} anions to produce \rm (NH_4)_2 SO_4.

Hence, the two products will be \rm Be(OH)_2 and \rm (NH_4)_2 SO_4.

Note that charges on the ions must balance. For example, a \rm Be^{2+} ion carries twice as much charge as an \rm {NH_4}^{+} ion. As a result, each \rm Be^{2+} ion would bond with twice as many \rm OH^{-} ions as \rm {NH_4}^{+} would in \rm NH_4 OH.

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What is the change in air pressure over a given distance called?.
emmainna [20.7K]
The change in pressure measured across a given distance called a Pressure Gradient. The pressure gradient creates a net force that is directed from higher to lower pressure and is called the Pressure Gradient Force. ... As air increases in velocity, it is deflected by the Coriolis Force.
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3 years ago
Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ
Oksi-84 [34.3K]

Answer:

The number is  Z = 216 \ fringes

Explanation:

From the question we are told that

      The wavelength is  \lambda  =  520 \ nm =  520 *10^{-9} \ m

       The length of the glass plates is y  = 21.1cm = 0.211 \ m

      The distance between the plates (radius of wire ) =  d =  0.028 mm  =  2.8 *10^{-5} \  m

   Generally the condition for constructive  interference in a film is mathematically represented as

            2 *  t  = [m +  \frac{1}{2}  ]\lambda

Where  t is the thickness of the separation between the glass i.e  

    t  = 0 at the edge where the glasses are touching each other and  

     t =  2d at the edge where the glasses are separated by the wire  

   m is the order of the fringe it starts from  0, 1 , 2 ...

So  

       2 *  2 * d   = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>   2 *  2 *   (2.8 *10^{-5}) = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>    

       m = 215

given that we start counting m from zero

   it means that the number of  bright fringes that would appear is

         Z =  m + 1

=>    Z =  215 +1

=>     Z = 216 \ fringes

3 0
3 years ago
.a car increases its speed from 10 m/s to 20/s in 2.5. seconds calculate it’s acceleration
Mekhanik [1.2K]

Answer:

\boxed {\boxed {\sf 4\ m/s^2}}

Explanation:

Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.

a= \frac{v_f-v_i}{t}

The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.

  • v_f= 20 m/s
  • v_i= 10 m/s
  • t= 2.5 s

Substitute the values into the formula.

a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }

Solve the numerator.

a= \frac{10 \ m/s}{2.5 \ s}

Divide.

a= 4 \ m/s/s

a= 4\ m/s^2

The acceleration of the car is <u>4 meters per second squared.</u>

3 0
3 years ago
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