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3 years ago

What is the weight of a rock that has a mass of 7kg?

Physics

1 answer:

sp2606 [1]3 years ago

8 0

In pounds your answer is 15.4324 or 15.4

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The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee

lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is $-27.3\hat{i}$

y component of vector is $43.6\hat{j}$

so position vector is

$r=-27.3\hat{i}+43.6\hat{j}$

Magnitude of vector is

$|r|=\sqrt{27.3^2+43.6^2}$

$|r|=\sqrt{2646.25}$

|r|=51.44 units

Direction

$tan\theta =\frac{43.6}{-27.3}=-1.597$

vector is in 2nd quadrant thus

$180-\theta =57.94$

$\theta =122.06^{\circ}$

4 0

3 years ago

Give me four reasons pluto is a cool planet / dwarf planet

AleksandrR [38]

Answer:

1. Just because it is small doesn't mean it needs to be excluded. If that were the case I would've been out of my friend group a while ago

2. Look at it it's fricking beautiful (see attachment)

3. It is just a great planet I don't think there needs to be any reason given I meannn you agree?

4. There's no other reason needed it's fricking gorgeous and amazing it needs no other reason. It needs a freaking

opening announcement to announce the arrival of the gorgeouness.

5 0

2 years ago

Read 2 more answers

Deduce a value for the latent heat of evaporation Lv of water. State clearly any simplifying assumptions that you make. Estimate

Stolb23 [73]

Find the below attachment

5 0

3 years ago

Read 2 more answers

All planets revolve around the sun counterclockwise,and most also rotate on their axis counterclockwise true or false

Vedmedyk [2.9K]

All the planets revolve around the sun counter clockwise and rotate on hteir axis counterclockwise except venus and neptune.

8 0

3 years ago

An electron is traveling at 0. 85c. what is its mass? (the rest mass is 9. 11 × 10-31 kg. )

egoroff_w [7]

The mass of the electron is $1.72\times 10^{-30}$ Kg.

<h3>How can we calculate the mass of the electron?</h3>

To calculate the mass of the electron we are using the formula,

$m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

Here we are given,

$m_0$ =The rest mass of an electron = $9. 11 \times 10^{-31}$ kg.

v= The velocity of electron = 0. 85c.

c= The velocity of light = c. (c= $3\times 10^8$ m/s)

We have to found the mass of an electron = m Kg.

Now we substitute the known values, we found that,

$m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-\frac{(0.85c)^{2} }{c^{2} } } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-(\frac{0.85c}{c})^2 } }$

Or, $m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-({0.85})^2 } }$

Or, $m=1.72\times 10^{-30}$ Kg.

From the above calculation we can conclude that, The mass of the electron is $1.72\times 10^{-30}$ Kg.

Learn more about electron:

brainly.com/question/860094

#SPJ4

4 0

1 year ago