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erik [133]
3 years ago
15

A ball rolls along the floor with a constant velocity of 6m/s. How far will it go in 10 sec?

Physics
1 answer:
Nady [450]3 years ago
5 0

Answer:

60m

Explanation:

.

X = V × t

X = 6 × 10 = 60m

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a particle is moving in a circle of radius R with constant speed.The time period of particle is T=1 second.In a time t=T/6,if th
12345 [234]


at t=T/6, total distance covered= 2*pi*r/6  and  displacement= r

 difference of them = 2*t
so, 2*pi*r/6- r =2(1/6)=1/3

r=1/(pi-3)=7.062


4 0
3 years ago
Read 2 more answers
An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi
poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2)   .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u     .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification =  203.62 / 96.5

magnification is 2.110

3 0
4 years ago
What is the lonar crater, India (Aisa)
GREYUIT [131]
Lonar Lake is a saline soda lake located at Lonar in Buldhana district, Maharashtra, India, which was created by a meteor impact during the Pleistocene Epoch and it is the only known hyper velocity impact crater in basaltic rock anywhere on Earth.
4 0
3 years ago
A racing car travels with a constant tangential speed of 80.8 m/s around a circular track of radius 602 m. (a) Find the magnitud
KatRina [158]

Answer:

10.84 m/s2 radially inward

Explanation:

As the car is traveling an a constant tangential speed of 80.8 m/s, the total acceleration only consists of the centripetal acceleration and no linear acceleration. The formula for centripetal acceleration with respect to tangential speed v = 80.8 m/s and radius r =602 m is

a = \frac{v^2}{r} = \frac{80.8^2}{602} = 10.84 m/s^2

b) The direction of this centripetal acceleration is radially inward

6 0
4 years ago
Why do quarterbacks throw the football with significant spin about its long axis?
Lera25 [3.4K]

(a) the principle of aerodynamic convergence

(b) the centripetal force

(c) Conservation of angular momentum

(d) Conservation of kinetic energy

(e) None of these

Conservation of angular momentum

Answer: Option C.

<u>Explanation:</u>

The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.

The law of conservation of angular momentum expresses that the angular energy of a body that is the result of its snapshot of latency about the hub of revolution and its rakish speed about a similar pivot, can't change except if an outside torque follows up on the framework.

7 0
4 years ago
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