Answer:
Explanation:
Potential at a point near a charge = Q / 4πε₀ R
where Q is charge given , R is distance of point from the charge .
Q / 4πε₀ R = 40
Electric field E at A = -dV / dR
= .16 x 10⁻³ / 2 x 10⁻⁶
= .08 x 10³
= 80 N/C
E = Q / 4πε₀ R²
80 = Q / 4πε₀ R x R
80 = 40 / R
R = 40 / 80
= .5 m .
Answer:

Explanation:

The relation between current through a metallic conductor and potential difference across its ends was studied systematically by a German physicist , <u>George </u><u>Simon </u><u>Ohm </u> in <u>1</u><u>8</u><u>2</u><u>6</u><u> </u><u>AD </u>. This relation is now known as Ohm's law. It states that <u>the </u><u>electric </u><u>current </u><u>passing </u><u>through</u><u> </u><u>a </u><u>conductor </u><u>is </u><u>directly </u><u>proportional</u><u> </u><u>to </u><u>the </u><u>potential </u><u>difference</u><u> </u><u>across </u><u>its </u><u>two </u><u>ends </u><u>at </u><u>a </u><u>constant </u><u>physical </u><u>condition</u><u> </u><u>[</u><u> </u><u>Temperature</u><u> </u><u>,</u><u> </u><u>cross </u><u>-</u><u> </u><u>sectional </u><u>area </u><u>,</u><u> </u><u>length </u><u>,</u><u> </u><u>nature </u><u>of </u><u>material </u><u>etc </u><u>]</u>
Hope I helped!
Best regards!!



Because the weight of one ball is mg = 147 N, the gravitational force between the two balls is
or
parts per billion of the weight.