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KatRina [158]
3 years ago
11

The current in a radio measures 12 amps. The resistance of the radio is 4 ohms. What is the voltage?

Physics
2 answers:
Sav [38]3 years ago
6 0

As per ohm's law we can say that voltage across the ends of a resistor is always product of the resistance with current flows through it.

So we can write

V = i*R

given that

i = 12 A

R = 4 ohm

now we can say from the above formula

V = 4 * 12

V = 48 Volts

alexgriva [62]3 years ago
5 0
Voltage = current * resistance
Voltage = 12 * 4
Voltage = 48V
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calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2​
igor_vitrenko [27]

First, balance the reaction:

_ KClO₃   ==>   _ KCl + _ O₂

As is, there are 3 O's on the left and 2 O's on the right, so there needs to be a 2:3 ratio of KClO₃ to O₂. Then there are 2 K's and 2 Cl's among the reactants, so we have a 1:1 ratio of KClO₃ to KCl :

2 KClO₃   ==>   2 KCl + 3 O₂

Since we start with a known quantity of O₂, let's divide each coefficient by 3.

2/3 KClO₃   ==>   2/3 KCl + O₂

Next, look up the molar masses of each element involved:

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• O: 15.999 g/mol

Convert 10 g of O₂ to moles:

(10 g) / (31.998 g/mol) ≈ 0.31252 mol

The balanced reaction shows that we need 2/3 mol KClO₃ for every mole of O₂. So to produce 10 g of O₂, we need

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3 years ago
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Answer:

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a=\dfrac{v-u}{t}\\\\a=\dfrac{10-30}{0.5}\\\\a=-40\ m/s^2

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