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KatRina [158]
3 years ago
11

The current in a radio measures 12 amps. The resistance of the radio is 4 ohms. What is the voltage?

Physics
2 answers:
Sav [38]3 years ago
6 0

As per ohm's law we can say that voltage across the ends of a resistor is always product of the resistance with current flows through it.

So we can write

V = i*R

given that

i = 12 A

R = 4 ohm

now we can say from the above formula

V = 4 * 12

V = 48 Volts

alexgriva [62]3 years ago
5 0
Voltage = current * resistance
Voltage = 12 * 4
Voltage = 48V
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A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the rul
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0.3858 Nm

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A 2.4 kg block is dropped onto a spring and platform of negligible mass. The block is released
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The speed of the block when the compression is 15 cm is 9.85 m/s.

The given parameters;

  • <em>mass of the block, m = 2.4 kg</em>
  • <em>height of the block, h =  5 m</em>
  • <em>compression of the spring, x = 25 cm = 0.25 m</em>

The spring constant is calculated as follows;

F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{2.4 \times 9.8}{0.25} \\\\k = 94.08 \ N/m

The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;

\Delta K.E = \Delta P.E\\\\\frac{1}{2} m(v^2  - v_{0 }^2 ) = mgh - \frac{1}{2} kx^2\\\\\frac{1}{2} mv^2  = mgh -   \frac{1}{2} kx^2\\\\mv^2   = 2mgh - kx^2\\\\v^2 = \frac{2mgh - kx^2}{m} \\\\v = \sqrt{\frac{2mgh - kx^2}{m}} \\\\v = \sqrt{\frac{(2 \times 2.4 \times 9.8 \times 5) - (94.08 \times 0.15^2)}{2.4}} \\\\v = 9.85 \ m/s

Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.

Learn more here:brainly.com/question/14289286

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