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KatRina [158]
3 years ago
11

The current in a radio measures 12 amps. The resistance of the radio is 4 ohms. What is the voltage?

Physics
2 answers:
Sav [38]3 years ago
6 0

As per ohm's law we can say that voltage across the ends of a resistor is always product of the resistance with current flows through it.

So we can write

V = i*R

given that

i = 12 A

R = 4 ohm

now we can say from the above formula

V = 4 * 12

V = 48 Volts

alexgriva [62]3 years ago
5 0
Voltage = current * resistance
Voltage = 12 * 4
Voltage = 48V
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Heating gas to create plasma can yield A) neutrons. B) elements. C) molecules. D) free electrons.
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That is why in this process there are always<u> free electrons</u>. Therefore in heating gas to create plasma can yield  free electrons, and the correct option is D.

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3 years ago
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3 years ago
In grinding a steel knife blade (specific heat = 0.11 cal/g-c),the metal can get as hot as 400C. If the blade has a mass of 80g,
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Answer:

33 g.

Explanation:

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As we have a limit for the maximum temperature of both elements (once reached a final thermal equilibrium), of 100ºC, which means that the maximum allowable change in temperature will be of 300º C for the knife, and of 80º C for the water.

Empirically , it has been showed that for a heat exchange process using only conduction, the heat needed to raise the temperature of a body, is proportional to the mass, being the proportionality constant a factor that depends on the material, called specific heat.

So, we can write the following equation:

cs*mk*Δtk = cw*mw*Δtw

Replacing by the givens of the question, we have:

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5 0
3 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
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