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3 years ago

Which of the following is a physical property?

Physics

2 answers:

coldgirl [10]3 years ago

6 0

Flammability, I think!

notsponge [240]3 years ago

6 0

The correctttt answer is A Density

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As the clump of colored fluid at the bottom of the lava lamp reaches the top, which has increased?

bagirrra123 [75]

the heat and mass...

6 0

4 years ago

Read 2 more answers

Determine the angle between the directions of vector a = 3.00i 1.00j and vector b = 1.00i 3.00j .

Katena32 [7]

The angle between the two vectors is 126° 52' 11".

The given parameters;

vector A = 3.00i + 1.00j

vector B = 1.00i + 3.00j

The angle between the two vectors is calculated as follows;

$cos \theta = \frac{A.B}{|A|.|B|}$

The dot product of vectors A and B is calculated as;

A.B = ( 3i + 1j ) . ( 1i +3j )

= ( 3 × 1 ) + ( 1 × 3 )

= 3 + 3

= 6

The magnitude of vectors A and B is calculated as;

|A| = $\sqrt[]{3^2 + 1^2} = \sqrt[]{10} \\$

|B| = $\sqrt[]{1^2 + 3^2} = \sqrt[]{10} \\$

The angle between in two vectors is calculated as;

$Cos \theta = \frac{6}{\sqrt[]{10}\sqrt[]{10} } \\\\Cos \theta = \frac{6}{\ 10 }\\\\Cos \theta = 0.6\\\\\theta = cos^-^1 (0.6)\\\\\theta = 126\\$

Therefore, the angle between the two vectors is 126° 52' 11".

Learn more about vectors here:

brainly.com/question/25705666

#SPJ4

6 0

2 years ago

What is being despited in this picture

yan [13]

Answer:

i am guessing for reflection but not so sure

8 0

3 years ago

Describe how a change in resistance would affect the current in a circuit.

Tresset [83]

Explanation:

The relation between potential difference, current and resistance flowing in a circuit is given by using Ohm's law. It can be given by :

V = IR

$I=\dfrac{V}{R}$

Resistance opposes the flow of electric current in the circuit. It means that, if resistance is more, less current will flow through the circuit.

3 0

3 years ago

A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.4 ft/s,

Art [367]

Answer:

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

Explanation:

given,

length of ladder = 10 ft

let x be the distance of the bottom and y be the distance of the top of ladder.

x² + y² = 100

differentiating with respect to time we get

$2 x\dfrac{dx}{dt}+2y\dfrac{dy}{dt} = 0$ ..............(1)

when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s

from equation (1)

now,

$16\times 1.4 + 12\dfrac{dy}{dt} = 0$

$\dfrac{dy}{dt} = -\dfrac{5.6}{3}$

let the angle between the ladders be θ

$tan\theta = \dfrac{y}{x}$

y = xtan θ

$\dfrac{dy}{dt} =\dfrac{dy}{dt} tan\theta + x sec^2\theta\dfrac{d\theta}{dt}$

$-\dfrac{5.6}{3} =1.4\times \dfrac{6}{8} + 8 (1+\dfrac{9}{16})\dfrac{d\theta}{dt}$

$\dfrac{25}{2} \dfrac{d\theta}{dt} =\dfrac{-17.5}{6}$

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

6 0

3 years ago