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valkas [14]
3 years ago
15

Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm

. pitch is 300 mm. Show your solution please coz i don't really know how to do it! thanks
Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

Step-by-step explanation:

Lets make it so simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = \sqrt{(3.14 * (600 - 20))^{2} + 300^{2}  x 16

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

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