Ask question

Ask question

All categories

2 years ago

10

Solve the word problem. The formula P = 6s gives the formula for the perimeter of a regular hexagon with side length s. What is

the perimeter of a regular hexagon with side length 3.4 cm?
Question options:

a: 18.8 cm

b: 3.4 cm

c: 9.4 cm

d: 20.4 cm

1 answer:

Lunna [17]2 years ago

6 0

The perimeter of the hexagon would be 20.4

To solve:

P=6s < plug In 3.4 in the S

P=6(3.4)

6×3.4= *20.4*

You might be interested in

Please help me find X ( I figured out the first part

zaharov [31]

Answer:

128

Step-by-step explanation:

X is a corresponding parallel angle, the angle opposite it which is 128 would be the same because they are parallel angles.

8 0

2 years ago

Luis is finding 9-6+2. Find his mistake and correct it

valina [46]

Luis is finding 5 because 9 minus 6 is 3. 3 plus 2 equal 5 easy

3 0

3 years ago

Standard normal curve between z=.42 and z=1.92<br> a= .6902<br> b= .3098<br> c= .1902<br> d= .8098

soldier1979 [14.2K]

The correct answer is Choice B: 0.3098.

To find the answer, you have to use a normal distribution table. Look up the percents for each z-score and subtract them to find the region between.

z = 1.92 the percent is 0.9726

z = 0.42 the percent is 0.6628

0.9726 - 0.6628 = 0.3098

4 0

2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

2 years ago

Tickets to a concert cost $70, or $20 with a student discount. Ticket sales must exceed $500,000 for the group to perform. If 20

Angelina_Jolie [31]

Solution:

Let x = the number of $70 seats sold

Let y = the number of $20 seats sold

x+y ≤ 20,000

70x+20y > 500,000

4 0

2 years ago

Read 2 more answers