Answer:
F= 56,1 N :
Explanation:
We apply Newton's first law for balancing forces system.
We take the x axis in the direction of the ramp with a 16.1° slope.
∑Fx= 0
∑Fx: algebraic sum of forces ( + to the right, - to the left)
Problem development:
Look at the free body diagram :
The only forces that act on the box are the weight and tension of the rope because there is no friction.
T: Rope tension (N)
W :Box weight (N)
∑Fx= 0
Tx-Wx=0
Tx =Tcos( 43.2°- 16.1°)= Tcos ( 27.1°)
Wx= W*sen 16.1°= m*g*sen 16.1°=18.4*9.8* sen 16.1° = 50N
Tcos ( 27.1°)-50=0
Tcos ( 27.1°) = 50
T = (50) / (cos ( 27.1°))
T = 56,1 N
T=F= 56,1 N
Amalgamating is the coating of zinc plate with mercury.
Any change in speed or direction of motion is acceleration.
Constant acceleration can mean ...
-- speeding up at a constant rate . . . gaining the same amount
of speed each second.
-- slowing down at a constant rate . . . losing the same amount
of speed each second.
-- changing direction at a constant rate . . . for example, going
around a circular path at a constant speed.
Its (a) and(a)for the other ? and the last one is (d)
Answer:
car B will be 30 Km ahead of car A.
Explanation:
We'll begin by calculating the distance travelled by each car. This is illustrated below:
For car A:
Speed = 40 km/h
Time = 3 hours
Distance =?
Speed = distance / time
40 = distance / 3
Cross multiply
Distance = 40 × 3
Distance = 120 Km
For car B:
Speed = 50 km/h
Time = 3 hours
Distance =?
Speed = distance / time
50 = distance / 3
Cross multiply
Distance = 50 × 3
Distance = 150 Km
Finally, we shall determine the distance between car B an car A. This can be obtained as follow:
Distance travelled by car B (D₆) = 150 Km
Distance travelled by car A (Dₐ) = 120 Km
Distance apart =?
Distance apart = D₆ – Dₐ
Distance apart = 150 – 120
Distance apart = 30 Km
Therefore, car B will be 30 Km ahead of car A.
