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Harman [31]
3 years ago
12

Se aplica una fuerza de 2.294N a una masa de 408 kg. ¿Cuál es la aceleración de la masa?

Physics
1 answer:
Zanzabum3 years ago
8 0

Answer:

a=5.62[m/s^2]

Explanation:

Acorde a la segunda ley de newton la cual dice que la sumatoria de fuerzas sobre un cuerpo el cual no esta en equilibrio estatico presentara una aceleracion. Esta fuerza sera igual al producto de la masa del cuerpo por su aceleracion.

F=m*a\\F=fuerza total aplicada [N]\\m=masa del cuerpo[kg]\\a=aceleracion del cuerpo[m/s^2]\\\\

De esta manera despejando el valor de aceleracion de la anterior ecuacion:

a=\frac{F}{m} \\a=2294/408\\a=5.62[m/s^2]

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denis23 [38]

Answer:

0.021 V

Explanation:

The average induced emf (E) can be calculated usgin the Faraday's Law:

E = - \frac{N*\Delta \phi}{\Delta t}  

<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

<em>Δt = is the time = 0.3 s   </em>

<em>A = is the loop of wire area = πr² = πd²/4 </em>

<em>ΔB: is the magnetic field = (0 - 1.04) T                     </em>

Hence the average induced emf is:

E = - \frac{\Delta B*A}{\Delta t} = - \frac{(0- 1.04 T) \pi (0.088 m)^{2}}{4*0.3 s} = 0.021 V                      

Therefore, the average induced emf is 0.021 V.

I hope it helps you!

8 0
4 years ago
The inner planets are different from the outer planets mainly because they are:.
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Answer:

The inner planets are closer to the Sun and are smaller and rockier. The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus , Earth and Mars.

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⦁ A car going 50 m/s is brought to rest in a distance of 20.0 m as it strikes a pile of dirt. How large an average force is exer
gtnhenbr [62]

Answer:

the average force exerted by seatbelts on the passenger is 5625 N.

Explanation:

Given;

initial velocity of the car, u = 50 m/s

distance traveled by the car, s = 20 m

final velocity of the after coming to rest, v = 0

mass of the passenger, m = 90 kg

Determine the acceleration of the car as it hit the pile of dirt;

v² = u² + 2as

0 = 50² + (2 x 20)a

0 = 2500 + 40a

40a = -2500

a = -2500/40

a = -62.5 m/s²

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The force exerted on the passenger by the backward action of the car is calculated as follows;

F = ma

F = 90 x 62.5

F = 5625 N

Therefore, the average force exerted by seatbelts on the passenger is 5625 N.

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3 years ago
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