All categories

3 years ago

Se aplica una fuerza de 2.294N a una masa de 408 kg. ¿Cuál es la aceleración de la masa?

Physics

1 answer:

Zanzabum3 years ago

8 0

Answer:

a=5.62[m/s^2]

Explanation:

Acorde a la segunda ley de newton la cual dice que la sumatoria de fuerzas sobre un cuerpo el cual no esta en equilibrio estatico presentara una aceleracion. Esta fuerza sera igual al producto de la masa del cuerpo por su aceleracion.

$F=m*a\\F=fuerza total aplicada [N]\\m=masa del cuerpo[kg]\\a=aceleracion del cuerpo[m/s^2]\\\\$

De esta manera despejando el valor de aceleracion de la anterior ecuacion:

$a=\frac{F}{m} \\a=2294/408\\a=5.62[m/s^2]$

You might be interested in

Two charges Q1 = +4 nC (positive) and Q2 = -2 nC (negative) are arranged in a line. Q1 is at the origin (x-0) and Q2 is at x=4 m

laila [671]

Answer:

Explanation:

Field due to a charge = k x Q / d²

field due to positive charge

=9 x 10⁹ x 4 x 10⁻⁹ / 1x1 = 36 N/C in positive x -direction.

Field due to negative charge

= 9 x 10⁹ x 2 10⁻⁹ / 3² = 2 N/C in positive x-direction.

Total field = 36 +2 = 38 N/C .

4 0

3 years ago

What is the Thermal energy firm Friction?

spin [16.1K]

Answer: Glad you ask!!

Its like a heat flow energy contained within a system that is responsible for its temperature.

Explanation:

deals with how heat is transferred between different systems and how work is done in the process

Hope this helps :)

4 0

3 years ago

Read 2 more answers

Pete Zaria works on weekends at Barnaby's Pizza Parlor. His primary responsibility is to fill drink orders for customers. He fil

laila [671]

Answer:

$W_n_e_t=7.648512 \approx 7.6J$

$K.E=0.8J$

$v=0.7844645406 \approx 0.78m/s$

Explanation:

From the question we are told that

Mass of pitcher $M= 2.6kg$

Force on pitcher $f=8.8N$

Distance traveled $48cm=>0.48m$

Coefficient of friction $\mu=0.28$

a)Generally frictional force is mathematically given by

$F=\mu N$

$F=0.28*2.6*9.8$

$F=7.1344N$

Generally work done on the pitcher is mathematically given as

$W_n_e_t=W_f+W_F$

$W_f=8.8*0.48=>4.224N\\W_F=7.1344*0.48=>3.424512N$

$W_n_e_t=4.224-3.424512$

$W_n_e_t=0.799488\approx 0.8J$

b)Generally K.E can be given mathematically as

$K.E= W_n_e_t$

Therefore

$K.E=0.8J$

c)Generally the equation for kinetic energy is mathematically represented by

$K.E=1/2mv^2$

$0.8=1/2mv^2$

Velocity as subject

$v=\sqrt{\frac{K.E*2}{m} }$

$v=\sqrt{\frac{0.8*2}{2.6} }$

$v=0.7844645406 \approx 0.78m/s$

6 0

3 years ago

Select the correct answer.

Nina [5.8K]

Answer:

Ос.

The spacing between particles increases.

Heat causes greater particle activity, and the particles

are farther apart.

3 0

3 years ago

Is there a difference between ragdoll and forward fold yoga pose

saul85 [17]

Answer:

Yess their is a difference the ragdoll pose is a genteler variation of the forward fold yoga pose.

Explanation:

In ragdoll pose, you are meant to relax your entire upper body, allowing for a deep release of tension or stress that is stored in your body.

4 0

3 years ago