C = 84.71%
H = 5.88%
O = 9.41%
<h3>Further explanation</h3>
Given
3-phenylphenol, C12H10O
Required
The mass percent
Solution
Ar C = 12 g/mol
Ar H = 1 g/mol
Ar O = 16 g/mol
MW C12H10O = 170 g/mol
The mass percent :
C = (12x12/170) x 100%
C = 84.71%
H = (10x1)/170) x 100%
H = 5.88%
O = (1 x 16)/170 x 100%
O = 9.41%
Answer:
CuO + H2SO4 = CuSO4 + H2O
Reaction type: double replacement
One mole of NaOH (Sodium hydroxide) is equal to 39.997 grams of NaOH.
Answer:
five point seventy four times ten to the power of eighth.
Explanation:
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