Answer:
134K
Explanation:
Using the ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas constant (0.0821 Latm/Kmol)
T = temperature (K)
Based on the information provided, n = 1.4moles, P = 3.25atm, V = 4.738L, T = ?
3.25 × 4.738 = 1.4 × 0.0821 × T
15.3985 = 0.11494T
T = 15.3985/0.11494
T = 133.969
Approximately;
T = 134K
Answer:
The answer would be B.
Explanation:
Ocean water near areas with low evaporation has higher salinity.
if im wrong please tell me .__.
Answer:
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
Chemical equation:
4Al(s) + 3O₂(l) → 2AlO₃(s)
Given data:
Mass of aluminium = 87 g
Moles of oxygen needed = ?
Solution:
Moles of aluminium:
Number of moles of aluminium= Mass/ molar mass
Number of moles of aluminium= 87 g/ 27 g/mol
Number of moles of aluminium= 3.2 mol
Now we will compare the moles of aluminium with oxygen.
Al : O₂
4 : 3
3.2 : 3/4×3.2 = 2.4 mol
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Answer: silicon Si, Germanium GE
Explanation:
