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Natali [406]
2 years ago
13

If the cell is somehow operated under conditions in which it produces a constant voltage of 1.50 V , how much electrical work wi

ll have been done when 0.487 mL of Br2(l) has been consumed
Chemistry
1 answer:
Yuri [45]2 years ago
8 0

For a cell  operated to produce a constant voltage of 1.50 V, the electrical work done  is mathematically given as

W=2.077*10^{-7}

<h3>What is the electrical work done?</h3>

Generally, the volume of Br2  is mathematically given as

Vb=\frac{0.38*3.12}{159.809}

Vb=7.18*10^-3ml

Therefore, the quantity of charge

q=(1.436*10^-2)*9.644*10^4

q=1.385^{-4}c

In conclusion, work done

W=Eq

W=1.50*1.385^{-4}

W=2.077*10^{-7}

Read more about Work

brainly.com/question/756198

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Answer:

HELIUM IS HE ANSWER

Explanation:

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8 0
3 years ago
What are the relationships between temperature and viscosity of water?
iris [78.8K]

Explanation:

Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.

temperature?

The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.

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8 0
3 years ago
What is the net ionic equation of the reaction of MgSO4 with Pb(NO3)2?
NemiM [27]

Hey there!:

Write the molecular equation for the reaction of MgSO4 with Pb(NO3)2 :

MgSO4(aq) + Pb(NO3)2(aq) ---> Mg(NO3)2(aq) + PbSO4(s)

Write the total ionic equation  for the reaction :

Mg²⁺ (aq) + SO₄⁻² (aq) + Pb²⁺ (aq) + 2 NO₃⁻¹ (aq) + PbSO₄(s)

Therefore:

Cancel the spectator ions on both sides:

Pb²⁺ (aq) + SO₄⁻² (aq) ---> PbSO4(s)


Hope that helps!

4 0
3 years ago
What tool did scientist use to first study the Earth’s interior
IgorC [24]
Seismic waves hope this helps.
5 0
3 years ago
How many moles of PC15 can be produced from 58.0 g of Cl₂ (and excess<br> P4)?
ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

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3 0
2 years ago
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