If the cell is somehow operated under conditions in which it produces a constant voltage of 1.50 V , how much electrical work wi
ll have been done when 0.487 mL of Br2(l) has been consumed
1 answer:
For a cell operated to produce a constant voltage of 1.50 V, the electrical work done is mathematically given as
W=2.077*10^{-7}
<h3>What is the
electrical work done?</h3>
Generally, the volume of Br2 is mathematically given as

Vb=7.18*10^-3ml
Therefore, the quantity of charge
q=(1.436*10^-2)*9.644*10^4
q=1.385^{-4}c
In conclusion, work done
W=Eq
W=1.50*1.385^{-4}
W=2.077*10^{-7}
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