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natulia [17]
4 years ago
12

When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt be

fore it overshoots the deck. in a typical landing, a jet touching down at 240 km/h is stopped in a distance of 95 m .\?
Physics
1 answer:
Veronika [31]4 years ago
8 0
The problem seems to be incomplete because there is no question. However, from the problem description, the logical question is to find he acceleration needed by the jet to land on the airplane carrier. The working equation would be:

2ad = v₂² - v₁²
Since the jet stops, v₂ = 0. Substituting the values:
2(a)(95 m) = 0² - [(240 km/h)(1000 m/1 km)(1h/3600 s)]²
Solving for a,
<em>a = -23.39 m/s² (the negative sign indicates that the jet is decelerating)</em>
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6 0
3 years ago
An emu moving with constant acceleration covers the distance between two points that are 92 m
nasty-shy [4]

Answer:

a) V_{o}=14.30 m/s

b) a=-0.046 m/s^{2}

Explanation:

The complete question is written below:

An emu moving with constant acceleration covers the distance between two points that are 92 m  apart in 6.5s. Its speed as it passes the second point is 14 m/s. What are (a) its speed at the first point and (b) its acceleration?

Since we are talking about constant acceleration, we can use the following equations:

d=x-x_{o}=(\frac{V_{o}-V}{2})t (1)

V=V_{o}+at (2)

Where:

d=92 m is the distance between the two points

V_{o} is the velocity of the emu at the first point

V=14 m/s is the velocity of the emu at the second point

t=6.5 s is the time it takes to the emu to cover the distance d

a is the emu's constant acceleration

Knowing this, let's begin with the answers:

<h2>a) Speed at the first point</h2>

In this situation wi will use equation (1):

d=(\frac{V_{o}-V}{2})t (1)

Finding V_{o}:

V_{o}=\frac{2d}{t}-V (3)

V_{o}=\frac{2(92 m)}{6.5 s}-14 m/s (4)

V_{o}=14.30 m/s (5)

<h2>b) Emu's acceleration</h2>

Now we will substitute (5) in equation (2):

14 m/s=14.30 m/s+a(6.5 s) (6)

Finding a:

a=-0.046 m/s^{2} (7) This means the emu is decreasing its speed at a constant rate.

8 0
3 years ago
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Alika [10]
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6 0
3 years ago
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vitfil [10]

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v = Δd / Δt

While acceleration is the rate of change in velocity over change in time, this is written as:

a = Δv / Δt

 

<span>Both quantities are vector quantities because negative values means that the acceleration or velocity is acting on the opposite direction.</span>

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3 years ago
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Answer:

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The explanation of this effect was made by Einstein in his explained of the photoelectric effect

8 0
3 years ago
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