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natulia [17]
3 years ago
12

When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt be

fore it overshoots the deck. in a typical landing, a jet touching down at 240 km/h is stopped in a distance of 95 m .\?
Physics
1 answer:
Veronika [31]3 years ago
8 0
The problem seems to be incomplete because there is no question. However, from the problem description, the logical question is to find he acceleration needed by the jet to land on the airplane carrier. The working equation would be:

2ad = v₂² - v₁²
Since the jet stops, v₂ = 0. Substituting the values:
2(a)(95 m) = 0² - [(240 km/h)(1000 m/1 km)(1h/3600 s)]²
Solving for a,
<em>a = -23.39 m/s² (the negative sign indicates that the jet is decelerating)</em>
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Answer:

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D.3

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2 years ago
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Firstly, let's calculate the momentum of both objects using p=mv:

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Object 2 (we will make this one negative as it is travelling in the opposite direction):
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Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

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