Given:
The mass of the sample is,
![m=3\text{ kg}](https://tex.z-dn.net/?f=m%3D3%5Ctext%7B%20kg%7D)
The volume is
![V=250\text{ cm}^3](https://tex.z-dn.net/?f=V%3D250%5Ctext%7B%20cm%7D%5E3)
To find:
The density
Explanation:
The volume is,
![\begin{gathered} V=250\text{ cm}^3 \\ =250\times10^{-6}\text{ m}^3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D250%5Ctext%7B%20cm%7D%5E3%20%5C%5C%20%3D250%5Ctimes10%5E%7B-6%7D%5Ctext%7B%20m%7D%5E3%20%5Cend%7Bgathered%7D)
The density is,
![\begin{gathered} d=\frac{m}{V} \\ =\frac{3}{250\times10^{-6}} \\ =12000\text{ kg/m}^3 \\ =12\times10^3\text{ kg/m}^3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Cfrac%7Bm%7D%7BV%7D%20%5C%5C%20%3D%5Cfrac%7B3%7D%7B250%5Ctimes10%5E%7B-6%7D%7D%20%5C%5C%20%3D12000%5Ctext%7B%20kg%2Fm%7D%5E3%20%5C%5C%20%3D12%5Ctimes10%5E3%5Ctext%7B%20kg%2Fm%7D%5E3%20%5Cend%7Bgathered%7D)
Hence, the density is
Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
F(g)= Gm1m2/ r^2
If mass is increased, so will the force of gravity because it is in direct relationship with the gravitational force, but if distance is increased, the force of gravity will decrease because it is indirectly related ( since it is on the bottom of the equation)
according to the second law of dynamics F = m • a => a = F / m