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Mrac [35]
3 years ago
13

A boat crosses a river of width 161 m in which the current has a uniform speed of 1.09 m/s. The pilot maintains a bearing (i.e.,

the direction in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 2.77 m/s relative to the water. What is the magnitude of the speed of the boat relative to a stationary shore observer? Answer in units of m/s.

Physics
1 answer:
hoa [83]3 years ago
7 0

Answer:

|v|=2.98m/s

Explanation:

In order to solve this problem we must first draw a diagram that will represent the situation. (See picture attached)

In this case the boat is being dragged by the river while it has a given velocity relative to the water and perpendicular to the flow of the river. We can take these velocities as vectors so we can add them up:

|v|=\sqrt{(1.09m/s)^{2}+(2.77m/s)^{2}}

which yields:

|v|=2.98m/s

so an observer that is stationary on the shore will se the boat having a speed of 2.98m/s.

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A nearsighted person wants to see an apple that is 7 meters away but can only clearly see objects that are at most 62 cm away fr
natulia [17]

Answer:

The power of the corrective lenses is 3.162 D.

Explanation:

Given that,

Object distance = 70 cm

Image distance = 62 cm

Distance between eyes and glasses = 2.5 cm

Eyeglasses made of diverging corrective lenses can help her to see the apple clearly

So now ,

Object distance from glass =70-2.5 = 67.5 cm

Image distance from glass = 62-2.5 = 59.5 cm

We need to calculate the focal length

Using formula for focal length

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{f}=-\dfrac{1}{59.5}-\dfrac{1}{67.5}

\dfrac{1}{f}=-\dfrac{508}{16065}\ cm

We need to calculate the power of lens

Using formula of power

P=\dfrac{100}{f}

P=-\dfrac{508}{16065}\times100

P=-3.162 \ D

Negative sign shows the lens is diverging.

Hence, The power of the corrective lenses is 3.162 D.

6 0
3 years ago
What are some ways you can vary your tone of voice to help you communicate effectively with others? A. Speaking aggressively
Leno4ka [110]
The answer is D, talking more loudly or quietly.
<span>
An expressive voice can bring totally different meaning to what you are saying. If you speak in a monotone voice, you are implying that you do not care about what you are saying or what the other person is talking about. If you speak expressively with some parts quieter or louder to make a point, it lets the listener know that you care about what you are saying and you care about what they have to say too. You can also emphasize a point by speaking louder or indicate that something is not as important by speaking softer.</span>

7 0
3 years ago
Read 2 more answers
An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
stich3 [128]

Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

ΔK=Kf-Ki=>1/2*m*vf^2-1/2*m*vi^2

P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
3 years ago
Which of the following explanations is correct about the wave that travels through the medium?
SVETLANKA909090 [29]
The correct answer is letter A
5 0
3 years ago
Pooping in my room and my room is upstairs and upstairs bathroom upstairs
diamong [38]

Answer:

huh? do you need help on math?

Explanation:

what do you mean?

7 0
2 years ago
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