As we know that sphere roll without slipping so there is no loss of energy in this case
so here we can say that total energy is conserved
Initial Kinetic energy + initial potential energy = final kinetic energy + final potential energy

as we know that ball start from rest

height of the ball initially is given as


also we know that

also for pure rolling

also we know that


now plug in all data in above equation




So speed at the bottom of the inclined plane will be 29 rad/s
Answer
The refracted wave must obey Snell's equation
Ni sin θi = Nr sin θr
If Nr differs from Ni then sin θr will differ from sin θi
If the wave originates from point A and ends at point B then Snell's Law shows that the time for light to get from point A to point B is a minimum.
Answer:
Neutralization reactions always produce water and a salt.
Explanation:
There are different types of chemical reactions that occurs. Two of them are neutralization and double-displacement reaction. Neutralization reaction is the reaction between an acid and a base to give an acid salt and water as products. For example:
2NaOH (base) + H2SO4 (acid) → Na2SO4 (salt) + 2H2O (water)
On the other hand, Double displacement reaction is the reaction that involves an ion exchange between the reactants to form new products. This ionic exchange occurs in such a way that two reactants form two new products. For example:
2NaCl + Ca(NO3)2 → CaCl2 + 2NaNO3
Therefore, the major difference between these two types of reactions is that: NEUTRALIZATION MUST ALWAYS PRODUCE WATER AND SALT AS PRODUCTS.
Mgraphs are proportional ofrelationships
Answer:
Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T
Explanation:
Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :
......(1)
Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.
In this problem,
Current, I = 0.7 A
Length of wire, L = 0.62 m
Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m
Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m
Substitute these values in equation (1).

B = 6.99 x 10⁻⁶ T