<u>Answer:</u> The expression for equilibrium constant in terms of concentration is ![K_c=[CO_2]](https://tex.z-dn.net/?f=K_c%3D%5BCO_2%5D)
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by 
For a general chemical reaction:

The
is written as:
![K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The concentration of pure solids and pure liquids are taken as 1.
For the given chemical reaction:

The expression for
is:
![K_{c}=\frac{[MgO][CO_2]}{[MgCO_3]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BMgO%5D%5BCO_2%5D%7D%7B%5BMgCO_3%5D%7D)
In the above expression, magnesium oxide and magnesium carbonate will not appear because they are present in solid state.
So, the expression for
becomes:
![K_{c}=[CO_2]](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5BCO_2%5D)
Hence, the equilibrium constant for the reaction is given above.
Answer:
Explanation:
Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M
Then, the dissociation of 4-chlorobutanoic acid can be expressed as:
⇄
+ 
The ICE table can be computed as:
⇄
+ 
Initial 0.76 - -
Change -x +x +x
Equilibrium 0.76 - x x x
![K_a = \dfrac{[\mathsf{C_3H_6ClCO_2^-}] [\mathsf{H^+}]}{\mathsf{[C_3H_6ClCO_2H ]}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5B%5Cmathsf%7BC_3H_6ClCO_2%5E-%7D%5D%20%5B%5Cmathsf%7BH%5E%2B%7D%5D%7D%7B%5Cmathsf%7B%5BC_3H_6ClCO_2H%20%5D%7D%7D)
![K_a = \dfrac{[x] [x]}{ [0.76-x]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5Bx%5D%20%5Bx%5D%7D%7B%20%5B0.76-x%5D%7D)
where:

![3.02*10^{-5} = \dfrac{x^2}{ [0.76-x]}](https://tex.z-dn.net/?f=3.02%2A10%5E%7B-5%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B%20%5B0.76-x%5D%7D)
however, the value of x is so negligible:
0.76 -x = 0.76
Then:


x = 0.00479 M
∴
0.00479 M
= (0.76 - 0.00479) M
= 0.75521 M
Finally, the percentage of the acid dissociated is;
= ( 0.00479 / 0.76) × 100
= 0.630 M
Calcium chloride dehydrate (CaCl₂ · 2 H₂O) have a molar mass equal to 147 g/mol.
Explanation:
To calculate the molar mass of calcium chloride dehydrate (CaCl₂ · 2 H₂O) we use the following formula:
molar mass of CaCl₂ · 2 H₂O = atomic weight of Ca × 1 + atomic weight of Cl × 2 + atomic weight of H × 4 + atomic weight of O × 2
molar mass of CaCl₂ · 2 H₂O = 40 × 1 + 35.5 × 2 + 1 × 4 + 16 × 2
molar mass of CaCl₂ · 2 H₂O = 147 g/mol
Learn more about:
molar mass
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<u>Answer:</u> The energy released in the given nuclear reaction is 94.99 MeV.
<u>Explanation:</u>
For the given nuclear reaction:

We are given:
Mass of
= 235.043924 u
Mass of
= 1.008665 u
Mass of
= 130.9061246 u
Mass of
= 88.9058483 u u
To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

(Conversion factor:
)

Hence, the energy released in the given nuclear reaction is 94.99 MeV.
Answer:
The substances made from polyvinyls are generally brittle and hard. This property prevails because the polymer strands present in the polyvinyls form a very regular and well-organized packing composition in the solid-state. The Van der Waals associations between the strands make the substance brittle. To make the substance soft and suitable to use as a raincoat, the incorporation of small molecules is done within the molten polymer before the hardening of the plastic.
These polymer strands act as plasticizers and prevent the strands of polymer from forming a hard and brittle conformation.