Answer:
3.3 moles of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH₃ + 5O₂ —> 6H₂O + 4NO
From the balanced equation above,
4 moles of NH₃ reacted to produce 6 moles of H₂O.
Finally, we shall determine the number of mole of H₂O produced by the reaction of 2.2 moles of NH₃. This can be obtained as follow :
From the balanced equation above,
4 moles of NH₃ reacted to produce 6 moles of H₂O.
Therefore, 2.2 moles of NH₃ will react to produce = (2.2 × 6)/4 = 3.3 moles of H₂O.
Thus, 3.3 moles of H₂O were obtained from the reaction.
The pH of normal rainwater is 5.6. It's slightly acidic
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
molarity of HCl=0.02117*10/1000
=2.117M
Answer:
Option D is correct.
Explanation:
Compared to a sample of helium at STP, the same sample of helium at a higher temperature and a lower pressure because any gas at a higher temperature and a lower pressure will behaves like an ideal gas. for eg.
nitrogen at STP show its behavior as an ideal gas.
When pressure of a gas increased & temperature is decreased then the gas does not follow ideal gas law.
Therefore option D is correct.
Number of millimoles of NaOH consumed in present titration =<span>33.23 X 0.09892
= 3.287
Thus, number of millimoles of vinegar present in sample = 3.287
Now, Molarity of vinegar solution = </span>
<span> = </span>
<span> = 0.1222 mol/dm3
Molar concentration of vinegar present in sample solution is 0.1222 M </span>
