Answer:
9.25
Explanation:
Let first find the moles of 
and 
number of moles of = 0.40 mol/L × 200 × 10⁻³L
= 0.08 mole
number of moles of = 0.80 mol/L × 50 × 10⁻³L
= 0.04 mole
The equation for the reaction is expressed as:
The ICE Table is shown below as follows:
Initial (M) 0.08 0.04 0
Change (M) - 0.04 -0.04 + 0.04
Equilibrium (M) 0.04 0 0.04
for buffer solutions
since they are in the same solution
Answer:
B
Explanation:
it is bigger then earth so it will have a greater mass.
Answer:
731.25 g
Explanation:
The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;
Molar mass of sodium chloride= 23.0 + 35.5 = 58.5 gmol-1
From the formula;
Number of moles (n) = mass /molar mass
Number of moles of sodium chloride= 12.5 moles
Mass of sodium = The unknown
Molar mass of sodium chloride= 58.5gmol-1
Mass of sodium chloride= number of moles × molar mass
Mass of sodium chloride= 12.5 × 58.5
Mass of sodium chloride= 731.25 g
Answer:
The conditions for biochemical, chemical and both standard states are shown below
Explanation:
Chemical standard state:
Temperature is 25°
Intial concntration of reactants and products is 1M
g. Presurre is 1 atm.
PH7
Biochemical standard state:
Temperature is 25°
PH7
Constant value of Mg2+
Both:
Intial concntration of reactants and products is 1M
g. Presurre is 1 atm.
Temperature is 25°
PH7
