Answer:
3. Speed is based on a specific direction
Step-by-step explanation:
Generally, speed is a scalar quantity equal to the magnitude of velocity. Velocity is a vector quantity that is speed together with a specific direction.
The answer choice that seems most in agreement with this description seems to be ...
3. Speed is based on a specific direction
Answer:
12
Step-by-step explanation:
so its at 12 visits because its their lowest common factor so i think it should be 12
Answer: 84
<u>Step-by-step explanation:</u>
Set up a proportion as follows: 

Cross multiply: 12x = 7 × 144
Divide by 12: x = 7 × 12
Simplify: x = 84
Question:
Prove that:

Answer:
Proved
Step-by-step explanation:
Given

Required
Prove

Subtract tan(10) from both sides


Factorize the right hand size

Rewrite as:

Divide both sides by 


In trigonometry:

So:
can be expressed as: 
gives


In trigonometry:

So:

Because RHS = LHS
Then:
has been proven