1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tensa zangetsu [6.8K]
4 years ago
10

Wendy makes a graphic organizer to help herself apply Ohm’s law to electric circuits.

Physics
2 answers:
Dima020 [189]4 years ago
5 0
The answer is answer choice B. 
Arte-miy333 [17]4 years ago
4 0

There simple rules for series and parallel circuits.
For the series circuits we have the following rules:
1)The same current flows through each part of a series circuit.(<span>I = I1 = I2 = I3)
2)</span>The total resistance of a series circuit is equal to the sum of individual resistances.(<span>Req = R1 + R2 + R3)
3)The</span> voltage applied to a series circuit is equal to the sum of the individual voltage drops.(<span>V = V1 + V2 + V3)
</span>For the parallel circuits we have the following rules:
1)Voltage is the same across each component of the parallel circuit.(<span>: V = V1 = V2 = V3)
</span>2)The sum of the currents through each path is equal to the total current that flows from the source.(<span> I = I1 + I2 + I3)
3)The total resistance is equal to the sum of the reciprocal value of individual resistors in the circuit.
The x region represents the series circuit. The y region represents a combination of series and parallel circuit. This means that for y region we can apply laws for both series and parallel circuits. 
So, all the equation can be applied to the y region.
However, not all equation can be applied to the x region. We can apply following equation to the x region:
1)</span><span>I = I1 = I2 = I3
</span>2)<span> V = V1 + V2 + V3
3)</span><span>Req = R1 + R2 + R3</span>
You might be interested in
Help!!
Ulleksa [173]

Answer:

5.5 KG is the mass

53.9 is the Weight

5 0
3 years ago
An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
aivan3 [116]

Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

Mass of water = 258 g

Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

7 0
3 years ago
When you speak into a cell phone, your sound waves must be converted into which other waveform in order to transmit the signal?
Inessa [10]
 ithey are converted to microwaves
7 0
3 years ago
Read 2 more answers
A 750-kg car moving at 23 m/s brakes to a stop. Assume that all the kinetic energy is transformed into thermal energy. The brake
ahrayia [7]

Answer:

The temperature of the brakes is 29.38°C.

Explanation:

Given that,

Mass of car = 750 kg

Speed = 23 m/s

Mass of iron = 15 kg

We need to calculate the kinetic energy of car

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

K.E=\dfrac{1}{2}\times750\times23^2

K.E=198.375\ kJ

We need to calculate the temperature of the brakes

Using formula of energy

K.E=mc\Delta T

Put the value into the formula

198.375=15\times0.450\times\Delta T

\Delta T=\dfrac{198.375}{15\times0.450}

\Delta T=29.38^{\circ}C

Hence, The temperature of the brakes is 29.38°C.

7 0
4 years ago
A system of satellites, base stations, and receivers is called ___________.
Nookie1986 [14]

A system of satellites, base stations, and receivers is called<span> global positioning system. </span><span>GPS, which stands for </span>Global Positioning System, is a radio navigation system that allows land, sea, and airborne users to determine their exact location, velocity, and time 24 hours a day, in all weather conditions, anywhere in the world. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
3 years ago
Other questions:
  • To the nearest tenth, what is the area of the shaded segment when JA=8ft ??
    13·2 answers
  • Gbenga needs to get glasses to correct his farsightedness. His eyes currently cannot focus on objects that are within 2 ft (or 6
    9·1 answer
  • Does the moon fall partly into earth's shadow when it is n "full"?
    7·1 answer
  • State the laws of vibration of a stringed Instrument​
    9·1 answer
  • A subtence floats or sinks in onother becauseof its relitivity
    14·1 answer
  • The 20-g bullet is travelling at 400 m/s when it becomes embedded in the 2-kg stationary block. The coefficient of kinetic frict
    11·2 answers
  • Indique onde em quantos metros o rapaz chegará com as seguintes condições: S0 = 0 a) v = 3 m/s e t = 2 s b) v = 2 m/s e t = 3,5
    13·1 answer
  • TRUE OR FALSE
    9·2 answers
  • In the apple-pulling-the orange sequence in this chapter, what is the force that accelerates the system across the floor?.
    8·1 answer
  • The equipotential surfaces associated with a point charge are
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!