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3 years ago

What is the common ratio for the geometric sequence?

Mathematics

2 answers:

Katarina [22]3 years ago

8 0

Your answer is 1:-4. This is because when you divide each term by -4, that is the number in the next term.

jekas [21]3 years ago

7 0

Answer:

1:-4

Step-by-step explanation:

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Alice purchased 4 1⁄2 kilograms of olive oil for $27. What is the price per kilogram

Bas_tet [7]

Do 27 divided by 4 1/2 or 4.5. That will be your answer. Let me know if this helps!

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3 years ago

Read 2 more answers

Modular arithmetic Pls a little explaine it

fredd [130]

Step-by-step explanation:

(72)¹⁴³ ≡ x (mod 7)

Since 72 ≡ 2 (mod 7),

72³ ≡ 2³ (mod 7) ≡ 1 (mod 7).

Therefore (72)¹⁴³ = (72³)⁴⁷ * (72²)

≡ 1⁴⁷ * 4 (mod 7) ≡ 4 (mod 7).

The answer is A.

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3 years ago

22.857142857142858 As a fraction

Mamont248 [21]

Answer:

Step-by-step explanation:

1. The answer is 8/35.

2. This works because 8/35 equals 22.857142857142858.

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1 year ago

deb has 25 buttons. her grandmother gives her more buttons. then deb gives her sister 11 buttons. now deb has 57 buttons. how ma

klemol [59]

The answer would be 43 .

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3 years ago

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

The question is incomplete:

"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago