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7nadin3 [17]
3 years ago
8

How many sucrose molecules are in 3.0 moles of sucrose

Chemistry
1 answer:
OverLord2011 [107]3 years ago
6 0
The molecular mass of sucrose is 342.3<span> grams per mole (g/mol).</span>
You might be interested in
Consider the electrolysis of molten barium chloride (bacl2). (a) write the half-reactions. include the states of each species..
IrinaK [193]

<span>Molten barium chloride is separetes:</span><span>
BaCl</span>₂(l) → Ba(l) + Cl₂(g), <span>
but first ionic bonds in this salt are separeted because of heat: 
BaCl</span>₂(l) → Ba²⁺(l) + 2Cl⁻(l).

Reaction of reduction at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).

Reaction of oxidation at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.

The anode is positive and the cathode is negative.

3 0
3 years ago
Titration Volume &amp; Concentration
polet [3.4K]

Answer:

18,1 mL of a 0,304M HCl solution.

Explanation:

The neutralization reaction of Ba(OH)₂ with HCl is:

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:

0,0171L*\frac{0,161moles}{L} = 2,7531x10⁻³moles of Ba(OH)₂

By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

2,7531x10^{-3}molBa(OH)_{2}*\frac{2molHCl}{1molBa(OH)_{2}} = 5,5062x10⁻³moles of HCl.

The volume of a 0,304M HCl solution for a complete neutralization is:

5,5062x10^{-3}molHCl*\frac{1L}{0,304mol} = 0,0181L≡18,1mL

I hope it helps!

4 0
3 years ago
Should a homeowner expect more caco3 buildup in hot water pipes or cold water pipes
Arturiano [62]
Answer:
             CaCO₃ built up in hot water pipes

Explanation:

The hardness of water is classified as;

Permanent Hard Water:
                                     In this the mineral content cannot be removed by boiling. This water contains mainly following,

                                        Calcium Sulfate  CaSO₄

                                        Calcium Chloride   CaCl₂

                                        Magnesium Sulfate   MgSO₄

                                        Magnesium Chloride   MgCl₂

These salts does not precipitate out on heating water.

Temporary Hard Water:
                                     In this water the mineral content can be removed by boiling. This water contains mainly following,

                                        Calcium Bicarbonate  Ca(HCO₃)₂

                                        Calcium Carbonate  CaCO₃

                                        Magnesium Bicarbonate   Mg(HCO₃)₂

                                        Magnesium Carbonate  MgCO₃

These salts does not precipitate out on heating water. i.e.

                Ca(HCO₃)₂    -------heat------>    CaCO₃  +  CO₂  +  H₂O

The CaCO₃ are formed in the form of scales.

Result:
           Hence, we can say that that CaCO₃ built up in hot water pipes.
5 0
3 years ago
Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro
Dahasolnce [82]

The product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

<h3>What is the reaction between sulfuric acid and potassium hydroxide?</h3>

The result will be, H+ from H₂SO₄ reacts with OH- from KOH to generate H₂O. Also, K+ reacts with SO₄²⁻ to create K₂SO4₄

As a result, the balanced equation will be:

\rm H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O

Thus, the product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. Sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

Learn more about potassium hydroxide

brainly.com/question/21904397

#SPJ1

6 0
3 years ago
How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

Thus,

0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity = 2.19 M

So,

2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

Volume = 0.0017927 L

Also, 1 L = 1000 mL

<u>So, volume = 1.7927 mL</u>

5 0
3 years ago
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