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7nadin3 [17]
3 years ago
8

How many sucrose molecules are in 3.0 moles of sucrose

Chemistry
1 answer:
OverLord2011 [107]3 years ago
6 0
The molecular mass of sucrose is 342.3<span> grams per mole (g/mol).</span>
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When can all the coefficients in a balanced equation represent volume ratios? when reactants and products are solids at stp when
Alexxx [7]

Answer: when reactants and products are gases at STP.


Justification:


1) STP stands for standard temperature (0°) and pressure (1 atm).


2) According to the kinetic molecular theory of the gases, and as per Avogadro's principle, equal volumes of gases, at the same temperature and pressure, have the same number of molecules.



3) Since the coefficients in a balanced chemical equation represent number of moles, when reactants and products are gases at the same temperature and pressure, the mole ratios are the same that the volume ratios, and then the coefficients of the chemical equation represent the volume ratios.


8 0
3 years ago
Read 2 more answers
Given a fixed amount of gas help at a constant pressure, calculate the temperature to which the gas would have to be changed if
PIT_PIT [208]

Answer:

592 K or 319° C

Explanation:

From the statement of Charles law we know that the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure. Thus;

V1/T1= V2/T2

Initial volume V1 = 1.75 L

Initial temperature T1= 23.0 +273 = 296 K

Final volume V2= 3.50 L

Final temperature T2 = the unknown

T2= V2T1/V1= 3.50 × 296 / 1.75

T2 = 592 K or 319° C

4 0
3 years ago
Why don't the oceans simply reabsorb the water that evaporates?
Misha Larkins [42]
The water evaporates into the clouds
6 0
3 years ago
During the water cycle, the sun's energy evaporates water from the surface of Earth. This water is the source of A) respiration.
LuckyWell [14K]
This water source is called precipitation
8 0
3 years ago
The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

R_2 = rate of effusion of oxygen gas = 14.0\text{ mL }min^{-1}

M_1 = molar mass of unknown gas  = ?

M_2 = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}

M_1=44.2g/mole

The unknown gas could be carbon dioxide (CO_2) that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide (CO_2)

5 0
4 years ago
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