100 times less H+
A solution at ph 10 contains<u> </u><u>100 times less H+</u> than the same amount of solution at ph 8.
<h3>The pH scale: How does it function?</h3>
- The pH scale determines how acidic or basic water is.
- The range is 0 to 14, with 7 representing neutrality.
- Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
- In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.
<h3>How does the pH change when two acids are combined?</h3>
- An acid's strength increases with the quantity of hydrogen ions it releases.
- The pH of the strong acids is between 1 and 2.
- We may observe that there is no response when two acids of the same strength are combined.
- It's because the end product will be neutral and the pH won't change.
<h3>How is pH value determined?</h3>
There are two ways to measure pH:
- colorimetrically with indicator fluids or sheets
- electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).
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Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g
<h3>Avogadro's hypothesis </h3>
6.02×10²³ atoms = 1 mole of arsenic
But
1 mole of arsenic = 75 g
Thus, we can say that:
6.02×10²³ atoms = 75 g of arsenic
<h3>How to determine the mass that contains 1.23×10²⁰ atoms</h3>
6.02×10²³ atoms = 75 g of arsenic
Therefore,
1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)
1.23×10²⁰ atoms = 0.0153 g of arsenic
Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic
Learn more about Avogadro's number:
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Characteristics of a Precipitate:
A precipitate is characterized by the following properties:
Appears as a solid species.
Settled down at the bottom of the reaction pot.
Insoluble in the corresponding solvent.
Answer:
13500 N
Explanation:
According to newtons second law of motion
mass m =1500 Kg
a = 9m/s^2
Force F = mass m × acceleration a
F = 1500×9= 13500 N
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
