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3 years ago

To separate a mixture of iron filings and salt, the most efficient method would be

Chemistry

2 answers:

CaHeK987 [17]3 years ago

7 0

Iron filings can be attracted by the magnet whereas salt can not. So the mixture can be separated by a magnet

Sloan [31]3 years ago

5 0

Answer:

passing a magnet through the mixture

Explanation:

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What kind of fossils can tell scientists what dinosaurs ate

Sunny_sXe [5.5K]

Coplorites I believe.

Hope this helps!

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5 0

3 years ago

Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution

dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

1. we calculate the moles of NaOH

$\tt mol=\dfrac{mass}{MW}$

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

$\tt mol=\dfrac{40~g}{40~g/mol}=1~mol$

2. Molarity(M)

$\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16$

5 0

3 years ago

Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other product

Greeley [361]

Answer:

a) N2 is the limiting reactant

b) 1215.9 grams NH3

c) 2283.6 grams H2

Explanation:

Step 1: Data given

Mass of N2 = 1000 grams

Molar mass N2 = 28 g/mol

Mass of H2 = 2500 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) +3H2(g) → 2NH3(g)

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 1000 grams / 28.0 g/mol

Moles N2 = 35.7 moles

Step 4: Calculate moles H2

Moles H2 = 2500 grams / 2.02 g/mol

Moles H2 = 1237.6 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. There will be consumed 35.7 moles.

H2 is in excess. There will react 3*35.7 = 107.1 moles

There will remain 1237.6 - 107.1= 1130.5 moles H2

This is 1130.5 * 2.2 = 2283.6 grams H2

Step 6: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 71.4 moles * 17.03 g/mol

Mass NH3 = 1215.9 grams NH3

7 0

3 years ago

261 nm to millimeters

Komok [63]

The answer is 0.000261 millimeters

5 0

3 years ago

Which of the following is an electrolyte? CH4OH O Ca(NO3)2 O C12H22011 O CH3CH2OH

Slav-nsk [51]

Answer:

O CH3CH2OH

Explanation:

5 0

3 years ago