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mars1129 [50]
3 years ago
11

What is the definition of a covalent bond?

Chemistry
2 answers:
kaheart [24]3 years ago
8 0
A chemical bond that involves the sharing of electron pairs between atoms
Anvisha [2.4K]3 years ago
6 0

Answer:

Covalent bond is the type of interaction that is occur by the sharing of electrons pair between the atoms.

Chemical bonding:

“Interactions that account for the association of atoms into molecules, ions, crystals, and other species are called chemical bonding”

Explanation:

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds.  

Types of chemical bonding:

1. Ionic bonding

2. Covalent bonding

3. Coordinate covalent bond/ Dipolar bonding

4. Metallic bonding

5. Intermolecular bonding

On the basis of the strength of chemical bond there are two types of bonding interactions;

• Primary bonding interactions (Strong bonding interactions)

(Ionic bond, Covalent bond and Metallic bond)

• Secondary bonding interactions (weak bonding interactions)

(Dipole-dipole interaction, London dispersion forces and hydrogen bonding)

Covalent Bonding

“Covalent bonding is a type of bonding, in which two or more atoms share valence electrons more or less equally”

 Types of covalent bonding

1. Single covalent bond

2. Double covalent bond

3. Triple covalent bond

The simplest and most common type is a single bond in which two atoms share two electrons. Other types include the double bond, the triple bond, one- and three-electron bonds, the three-center two-electron bond and three-center four-electron bond.

4. Polar covalent bond  

5. Non-Polar covalent bond

Polar covalent bond

A polar covalent bond is a covalent bond with a significant ionic character. This means that the two shared electrons are closer to one of the atoms than the other, creating an imbalance of charge. Such bonds occur between two atoms with moderately different electronegativities and give rise to dipole–dipole interactions. The electronegativity difference between the two atoms in these bonds is 0.3 to 1.7.

Non-Polar covalent bond

In nonpolar covalent bonds, the electronegativity difference between the bonded atoms is small, typically 0 to 0.3. Bonds within most organic compounds are described as covalent.  

Molecules which are formed primarily from non-polar covalent bonds are often immiscible in water or other polar solvents, but much more soluble in non-polar solvents such as hexane.

 


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In healthcare settings where sterilization is an absolute necessity, what method of sterilization will typically be used?
tester [92]

Answer:

Disinfecting (or boiling)

Explanation:

They'd want to disinfect everything so that it is germless. Boiling is a possible answer as well because you can boil certain things to rid them of germs.

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1 Condensation
larisa86 [58]

Answer:

Explanation:

A ) Solar Radiation

B ) Evaporation

C ) Transpiration

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E ) Precipitation

F ) Run Off

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3 0
3 years ago
The reactants in a chemical reaction contain 900 J of chemical energy. The products of the reaction contain 9000 J of chemical e
Agata [3.3K]

Answer:The reaction absorbs 8100 J of energy from the surroundings as it proceeds.

Explanation:

7 0
3 years ago
Read 2 more answers
Five million gallons per day (MGD) of wastewater, with a concentration of 10.0 mg/L of a conservative pollutant, is released int
hjlf

Answer:

a) The concentration in ppm (mg/L) is 5.3 downstream the release point.

b) Per day pass 137.6 pounds of pollutant.  

Explanation:

The first step is to convert Million Gallons per Day (MGD) to Liters per day (L/d). In that sense, it is possible to calculate with data given previously in the problem.  

Million Gallons per day 1 MGD = 3785411.8 litre/day = 3785411.8 L/d

F_1 = 5 MGD (\frac{3785411.8 L/d}{1MGD} ) = 18927059 L/d\\F_2 =10 MGD (\frac{3785411.8 L/d}{1MGD} )= 37854118 L/d

We have one flow of wastewater released into a stream.  

First flow is F1 =5 MGD with a concentration of C1 =10.0 mg/L.

Second flow is F2 =10 MGD with a concentration of C2 =3.0 mg/L.  

After both of them are mixed, the final concentration will be between 3.0 and 10.0 mg/L. To calculate the final concentration, we can calculate the mass of pollutant in total, adding first and Second flow pollutant, and dividing in total flow. Total flow is the sum of first and second flow. It is shown in the following expression:  

C_f = \frac{F1*C1 +F2*C2}{F1 +F2}

Replacing every value in L/d and mg/L

C_f = \frac{18927059 L/d*10.0 mg/L +37854118 L/d*10.0 mg/L}{18927059 L/d +37854118 L/d}\\C_f = \frac{302832944 mg/d}{56781177 L/d} \\C_f = 5.3 mg/L

a) So, the concentration just downstream of the release point will be 5.3 mg/L it means 5.3 ppm.

Finally, we have to calculate the pounds of substance per day (Mp).  

We have the total flow F3 = F1 + F2 and the final concentration C_f. It is required to calculate per day, let's take a time of t = 1 day.  

F3 = F2 +F1 = 56781177 L/d \\M_p = F3 * t * C_f\\M_p = 56781177 \frac{L}{d} * 1 d * 5.3 \frac{mg}{L}\\M_p = 302832944 mg

After that, mg are converted to pounds.  

M_p = 302832944 mg (\frac{1g}{1000 mg} ) (\frac{1Kg}{1000 g} ) (\frac{2.2 lb}{1 Kg} )\\M_p = 137.6 lb

b) A total of 137.6 pounds pass a given spot downstream per day.

4 0
3 years ago
PLEASE HELP ME WITH THIS I WILL GIVE YOU POINTS
eduard

Answer:

1. a

2. c

3. b

4. f

5. d

6. e

Explanation:

7 0
3 years ago
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