Question

At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations of 0.800 M, calculate the equilibrium concentrations of the gases. Equilibrium concentration of SO2-M Equilibrium concentration of NO2M Equilibrium concentration of SO3 Equilibrium concentration of NO

Answer 1

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] =  0.563 M

[SO3]=[NO] =  1.04 M

Explanation:

Given:

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

To determine:

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

         $SO2(g) + NO2(g)\rightleftharpoons SO3(g) + NO(g)$

I                0.800      0.800                                  0.800       0.800

C                -x               -x                                         +x             +x

E              (0.800-x)   (0.800-x)                             (0.800+x)   (0.800+x)

The equilibrium constant is given as:

$Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

$3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M