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3 years ago

A car has a displacement of 160 kilometers to the north in 2 hours. What is it’s velocity in kilometers per hour

Chemistry

1 answer:

Katen [24]3 years ago

3 0

I will show you a method to find the velocity:-

1) Find average velocity when acceleration is constant.

2) Set up an equation with position and time instead.

3) Find the distance between the start and end points.

4) Calculate the change in time.

5) Divide the total displacement by the total time.

6) Solve problems in two dimensions.

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Select the correct terms to complete the statement:

Likurg_2 [28]

Answer:

The particles that make up a substance in its liquid state have <u>more </u>kinetic energy than those of the same substance in its solid-state.

For a solid to melt, energy must be <u>added to</u> the system.

For a liquid to freeze, energy must be <u>removed from</u> the system.

5 0

2 years ago

Calculate the molality and van’t Hoff factor (i) for the following aqueous solutions:

MissTica

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of Van t Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

<h3>Which has highest Van t Hoff factor?</h3>

The Van't Hoff factor will be highest for

A. Sodium chloride.

B. Magnesium chloride.

C. Sodium phosphate.

D. Urea.

Learn more about van't off factor here:

<h3>brainly.com/question/22047232</h3><h3 /><h3>#SPJ4</h3>

3 0

1 year ago

Binary molecular (covalent) compounds are formed as the result of a reaction between two nonmetals. Although there are no ions i

ollegr [7]

Answer:

Binary molecular compounds are the compounds consisting of two non-metallic elements. Examples of binary molecular compounds include: NO2, HCl, HF, P2O5 e.t.c.

Rules For Naming Binary Molecular Compounds

Naming binary molecular compounds is quite easy,

1. The first element is given its name.

2. The second element is given its root name (such as, hydro, carb,ox, chlor e.t.c.) followed by suffix <em>ide.</em>

Name of N2O4 - Dinitrogen tetraoxide

Chemical Formula of;

iodic acid: HI

disulfur trioxide: S2O3

dinitrogen monoxide: N2O

hydrofluoric acid: HF

Difference between Binary acid and an oxyacid

An oxyacid is an acid consisting of an oxygen atom bonded to a hydrogen atom and at least one other non-metallic element. Examples of oxyacids include HNO3, H2SO4 e.t.c.

Binary acids are the acids consisting of hydrogen atom bonded to a non-metallic element. Examples include HF, HCl, HI e.t.c.

7 0

3 years ago

Read 2 more answers

Pb(NO3)2+K2CrO4 --> PbCrO4+KNO3 <br> How do you balance this?

belka [17]

Answer:

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

Step-by-step explanation:

The unbalanced equation is

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + KNO₃

Notice that the complex groups like NO₃ and CrO₄ stay the same on each side of the equation.

One way to simplify the balancing is to replace them with a single letter.

(a) For example, let <em>X = NO₃</em> and <em>Y =CrO₄</em>. Then, the equation becomes

PbX₂ + K₂Y ⟶ PbY + KX

(b) You need 2X on the right, so put a 2 in front of KX.

PbX₂ + K₂Y ⟶ PbY + 2KX

Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃

5 0

3 years ago

Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a

rewona [7]

<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

$Moles=\frac{mass}{molar mass}$

Therefore;

Moles of the compound will be;

$=\frac{0.030}{312g/mol}$

= 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23 molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0

3 years ago