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3 years ago

blank is the energy required for a chemical reaction to take place, and blank is the energy associated with every substance.

Chemistry

2 answers:

Korolek [52]3 years ago

5 0

Heat is the first one...and the secound one is kinetic

Pie3 years ago

5 0

Answer:

1) Activation energy

2) Internal energy

Explanation:

A reaction takes place is the reactants have a certain minimum amount of energy known as threshold energy.

All the reactants have some inherent energy known as internal energy, which corresponds to the potential, kinetic, vibrational, roational etc energy of the substance.

The rest amount of energy required by the reactants is known as activation energy. This the minimum extra amount of energy required to reach or cross the threshold energy level.

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Questlon 23 of 30

aleksklad [387]

A social culture i believe

4 0

3 years ago

Calculate the volume of a tin block that has a mass of 95.04 grams at STP. Your response must include both a numerical setup and

Ahat [919]

Answer:

Explanation:

As the problem states that we have STP, these conditions are 1 atm of pressure and 273 K of temperature.

Now, the equation we must use to solve this:

PV = nRT

Solving for V:

V = nRT/P

Where:

V: Volume in Liters

n: moles of the tin block

T: temperature in K

P: Pressure in atm

R: gas constant which is 0.082 L atm / K mol

But also the problem is giving us the density data for all elements. In the case of Tin it is 7.31 g/cm³ or 7.31 g/mL, so, with the formula of density:

d = m/V ----> V = m/d

From the above formula, we can calculate the volume of tin so:

V = 95.04 / 7.31

V = 13 mL

This would be the volume of the tin block, but, we have this block at STP so we need to calculate the volume with the ideal gas equation above. We need the molecular mass of Tin which is 118.71 g/mol, so let's calculate the moles:

n = m/MM

n = 95.04 / 118.71 = 0.8 moles

Now, solving for V:

V = 0.8 * 0.082 * 273 / 1

V = 17.91 L

And this would be the volume of the tin block at STP conditions.

3 0

2 years ago

The volume of a sample of a gas at 273 c is 200.0 l. if the volume is decreased to 100.0 l at constant pressure, what will be th

Lyrx [107]

It will also be halved... but the relationship is with Kelvin not c. So 273 +273 = 546 K. half of that is 273 K, then subtract 273... you get 0 degrees c

7 0

3 years ago

13. An aerosol spray can of deodorant with a volume of 0.410 L contains 3.0 g of propane gas (CH3) as propellant. What is the pr

qaws [65]

Answer: The pressure in the can is 4.0 atm

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = ?

V = Volume of gas = 0.410 L

n = number of moles = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{3.0g}{44.1g/mol}=0.068mol$

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $20^0C=(20+273)K=293K$

$P=\frac{nRT}{V}$

$P=\frac0.068mol\times 0.0820 L atm/K mol\times 293K}{0.410L}=4.0atm$

Thus the pressure in the can is 4.0 atm

8 0

2 years ago

Calculate the concentration of acetate ion in a buffer solution made from 2.00 mL of 0.50 M acetic acid and 8.00 mL of 0.50 sodi

Lelu [443]

Answer:

1 M

Explanation:

Equation of reaction is;

CH3COOH + CH3COONa -------------------> 2CH3COO^- + NaH

1 moles of each of the reactants react to give 2 moles of the acetate ion.

From the question, we have that 2.00 mL that is (2÷1000)L of 0.50 M acetic acid reacted with 8.00 mL that is (8/1000)L of 0.50 sodium acetate.

Then from equation, n = CV -------------------------------------------(1).

Where n= number of moles, V= volume, C= concentration.

Number of moles,n of acetic acid = 0.50M× 2/1000L.

n(acetic acid)= 0.001 moles.

Number of moles,n of sodium acetate= 0.50M ×(8/1000)L.

n(sodium acetate)= 0.004 moles.

0.001 moles of acetic acid react with 0.004 moles of Sodium acetate

Therefore, acetic acid is the limiting reagent.

One mole of acetic acid produces 2 moles of acetate ion.

0.001 mole of acetic acid produces= 0.002 moles of acetate ion.

Using the equation (1) that is, n= CV.

0.002= C× 2/1000

C= 0.002/0.002

C= 1 M

8 0

3 years ago