Question

A compound has the percent composition 47.40% Pd, 28.50% O, 21.40% C, and 2.69% H. Based on this information, which molecular formulas could represent the compound?
PdO2C2H3
Pd(O2CCH3)2
Pd(O2C2H3)3
PdO4C2H9
Pd2C8H12O8

Answer 1

Answer:

Pd(O2CCH3)2

Pd2C8H12O8

Explanation:

Given:

% Pd = 47.40

% O = 28.50

% C = 21.40

% H = 2.69

To determine:

Molecular formula of the compound containing Pd, O, C and H

Calculation:

Let the mass of the compound = 100g

Therefore based on the % compositions:

Mass of Pd = 47.40g

Mass of O = 28.50g

Mass of C = 21.40g

Mass of H = 2.69g

Atomic mass of Pd = 106.42 g/mol

Atomic mass of O = 15.99 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of H = 1.00 g/mol

$moles\ of\ Pd = \frac{47.40g}{106.42g/mol} =0.4454$

$moles\ of\ O = \frac{28.50g}{15.99g/mol} =1.782$

$moles\ of\ C = \frac{21.40g}{12.01g/mol} =1.782$

$moles\ of\ H= \frac{2.69g}{1.00g/mol} =2.690$

Ratio:

$Pd = \frac{0.4454}{0.4454} = 1.00\\\\O = \frac{1.782}{0.4454} = 4.00\\\\C = \frac{1.782}{0.4454} = 4.00\\\\H = \frac{2.690}{0.4454} = 6.039$

The empirical formula is : PdO4C4H6

Molecular formula = n(Empirical formula)

If n = 1

Molecular formula = PdO4C4H6 i.e. Pd(O2CCH3)2

If n= 2

Molecular formula = 2(PdO4C4H6)= Pd2O8C8H12

Answer 2

Answer:

Pd(O₂CCH₃)₂

Explanation