Answer:
10.3 g of oxygen are formed when 26.4 g of potassium chlorate is heated
Explanation:
This is the balanced equation:
2KClO₃(s) → 2KCl(s) + 3O₂(g)
Ratio beteween the salt and oxygen is 2:3
Molar mass of KClO₃ = 122.55 g/m
Let's find out the moles of salt
Mass / Molar mass
26.4 g /122.55 g/m = 0.215 moles
So, this is the final rule of three:
If 2 moles of KClO₃ make 3 moles of oxygen
0.215 moles of KClO₃ make (0.215 .3) /2 = 0.323 moles of O₂ are produced
Molar mass O₂ = 32 g/m
Moles . molar mass = mass
0.323 m . 32g/m = 10.3 g
Answer:
Look for extra things to do, small details, until you find a big enough one to go off that to continue
Explanation:
n/a
Answer:
the concentration of the reactants
the temperature in heating
If you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?
3.9 g + 12.7 g = 16.6 g
The sum of the masses of potassium and iodine equals the mass of the product, potassium iodide. The results are consistent with he law of conservation of mass.
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