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sp2606 [1]
4 years ago
12

How long will it take a car to go from a complete stop to 450 m/s if it is accelerating at 60.5 m/s2?

Physics
1 answer:
Semmy [17]4 years ago
4 0

Answer:

7.44 seconds

Explanation:

v = at + v₀

where v is the final velocity,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given v = 450 m/s, v₀ = 0 m/s, and a = 60.5 m/s²:

450 = (60.5)t + 0

t ≈ 7.44

It takes approximately 7.44 seconds.

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The astronaut's mass doesn't change.  It's the same wherever he goes,
because it doesn't depend on what else is around him.

His weight depends on what else is near him, so it changes, depending
on where he is.

         Weight  =  (mass) x (gravity)

On Earth,  Weight = (145 kg) x (9.81 m/s²)  =  1,422.5 newtons.
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On the moon, Weight = (145 kg) x (1.62 m/s²)  =  234.9 newtons.
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3 years ago
Era that we live in <br> 1. precambrian time<br> 2. mesozoic<br> 3. paleozoic<br> 4. cenozoic
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I believe we live in the Cenozoic era

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8 0
3 years ago
Which task would a colorectal surgeon perform?
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Air at 80 kPa and 127 °C enters an adiabatic diffuser steadily at a rate of 6000 kg/h and leaves at 100 kPa. The velocity of the
Vinil7 [7]

Answer:

a) The exit temperature is 430 K

b) The inlet and exit areas are 0.0096 m² and 0.051 m²

Explanation:

a) Given:

T₁ = 127°C = 400 K

At 400 K, h₁ = 400.98 kJ/kg (ideal gas properties table)

The energy equation is:

q-w=h_{2} -h_{1} +\frac{V_{2}^{2}-V_{1}^{2}    }{2} +delta-p

For a diffuser, w = Δp = 0

The diffuser is adiabatic, q = 0

Replacing:

0-0=h_{2} -h_{1} +\frac{V_{2}^{2}-V_{1}^{2}    }{2} +0

Where

V₁ = 250 m/s

V₂ = 40 m/s

Replacing:

0-0=h_{2} -400x10^{3}  +\frac{40^{2}-250^{2}      }{2} +0\\h_{2} =431430 J/kg=431.43kJ/kg

Using tables, at 431.43 kJ/kg the temperature is 430 K

b) The inlet area is:

m=\frac{P_{1} }{RT_{1} } A_{1} V_{1} \\\frac{6000}{3600} =\frac{80}{0.287*400} A_{1} *250\\A_{1} =0.0096m^{2}

The exit area is:

m=\frac{P_{2} }{RT_{2} } A_{2} V_{2} \\\frac{6000}{3600} =\frac{100}{0.287*430} A_{2} *40\\A_{2} =0.051m^{2}

6 0
3 years ago
An incident ray strikes a boundary at a 72.5-degree angle, resulting in an angle of refraction of 39.6 degrees. The index of ref
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A. Medium 1 is air. The refractive index of air is 1.0003. Refractive index is a measure of the bending of a ray of light when passing from one medium to another. If i is the angle of incidence of a ray in vacuum and r is the angle of refraction, the refractive index n is defined as the ratio of the sine angle of incidence to the sine of the angle of refraction; that is, n= sin i/ sin r. Refractive index may also be given by the velocity of light in medium 1 divided by the velocity of light in medium 2.


b. In this case the refractive index = sin 72.5/sin 39.6 
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but n = x/ 1.0003 = 1.4962
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Hence the refractive index of medium 2 is 1.4967. 
I therefore think that medium 2 is toluene; since it has a similar refractive index.

7 0
3 years ago
Read 2 more answers
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