Answer:
mgh₁ + ½mv₁² = mgh₂ + ½mv₂²
Explanation:
Initial total energy = final total energy
PE₁ + KE₁ = PE₂ + KE₂
mgh₁ + ½mv₁² = mgh₂ + ½mv₂²
Answer:
15 cm
Explanation:
= Diameter of the coin = 15 mm
= Diameter of the image of coin = 5 mm
= distance of the coin from mirror = 15 cm
= distance of the image of coin from mirror = ?
Using the equation


= - 5 cm
= radius of curvature
Using the mirror equation


= - 15 cm
Answer: 6.47m/s
Explanation:
The tangential speed can be defined in terms of linear speed. The linear speed is the distance traveled with respect to time taken. The tangential speed is basically, the linear speed across a circular path.
The time taken for 1 revolution is, 1/3.33 = 0.30s
velocity of the wheel = d/t
Since d is not given, we find d by using formula for the circumference of a circle. 2πr. Thus, V = 2πr/t
V = 2π * 0.309 / 0.3
V = 1.94/0.3
V = 6.47m/s
The tangential speed of the tack is 6.47m/s
Responder:
<h2>
490 julios
</h2>
Explicación:
Se dice que el trabajo se realiza cuando una fuerza aplicada a un objeto hace que el objeto se mueva a través de una distancia. El trabajo realizado por un cuerpo se expresa mediante la fórmula;
Workdone = Fuerza * Distancia
Como Fuerza = masa * aceleración,
Workdone = masa * aceleración * distancia
Masa dada = 5.0kg, aceleración = 2.0m / s² d =?
Para obtener d, usaremos una de las leyes del movimiento,
d = ut + 1 / 2at²
u = 0 (ya que el cuerpo acelera desde el reposo) yt = 7.0s
d = 0 + 1/2 (2) (7) ²
d = 49m
Workdone = 5 * 2 * 49
Workdone = 490 Julios
To calculate the mass of the fuel, we use the formula

Here, m is the mass of fuel, V is the volume of the fuel and its value is
and
is the density and its value of 0.821 g/mL.
Substituting these values in above relation, we get
Thus, the mass of the fuel 247 .94 kg.