Answer:
f = 10, g = 4.8 cm
Step-by-step explanation:
Area of ABCE = 60 cm²
Area of ABCD = 48 cm²
So,
Area of ADE = 60-48
=> 12 cm²
Area of ADE = 
<u><em>Where Area = 12 cm², Base = 4 cm</em></u>
12 = 
Height = 12-2
Height = 10 cm
Where Height is AD
So, AD = 10 cm
Also, <u><em>AD is parallel and equal to BC</em></u>
<u><em></em></u>
So,
f = 10 cm
<u><em>Now, Finding g</em></u>
Area of ABCD = 
<u><em>Where Area = 48 cm², Base = 10 cm</em></u>
48 = 10 * Height
Height = 48/10
Height = 4.8 cm
Whereas, Height is g
So, g = 4.8 cm
Answer:
-(x-8)(x+6)
Step-by-step explanation:
-x^2+2x+48
-(x^2-2x-48)
-(x-8)(x+6)
The trick is to find two numbers that when they multiply, you get the third term, which in this case, is -48. And when you add those two numbers, you get the second term, which is -2 in this case. The two numbers in this case are -8 and 6.
Answer:
$1.65
Step-by-step explanation:
Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
---
Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
