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3 years ago

A farmer performs an experiment to find the amount of fertilizer needed to increase crop yields. She uses different

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

Step-by-step explanation:

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The regular price for a sweater is $48. The store is having a buy one get one 1/2 off sale. If you buy 4 sweaters for that price

arsen [322]

48+48(the two sweaters you pay full price for)+48(the two half off sweaters are 24$ a piece) so your total for all four sweaters is 144$

4 0

3 years ago

Help! what is the surface area of the figure?

rjkz [21]

Answer:

220 cm^2

Step-by-step explanation:

3 0

3 years ago

Identify the function shown in this graph.

nadezda [96]

Answer:

Step-by-step explanation:

The functions are written in slope-intercept form.

The graph crosses the y-axis at (0,-2), so the y-intercept is -2.

You can eliminate D because its y-intercept is +2, not -2.

(1,1) and (0,-2) are points on the line.

The slope of the line is (-2-1)/(0-1) = 3

You can eliminate B because its slope is ⅓.

Eliminate C because its slope is -3, not 3.

Answer B

4 0

3 years ago

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago

Please answer ASAP. What is the negative angle of rotation for the angle with positive angle

Reil [10]

Answer:

-90

Step-by-step explanation:

The full circle is 360 degrees, so is you turn one way say 10 degrees, then you would need to move 350 degrees in opposite direction.

So, in this case moving 270 one way would be equivalent to moving 360-270=90 degrees in the opposite direction

8 0

3 years ago

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