Answer:
let current flow be x
Explanation:
than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v
This question involves the concepts of the equations of motion, kinetic energy, and potential energy.
a. The kinetic energy of the rocket at launch is "3.6 J".
b. maximum gravitational potential energy of the rocket is "3.6 J".
<h3>a. KINETIC ENERGY AT LAUNCH</h3>
The kinetic energy of the rocket at launch is given by the following formula:

where,
- K.E = initial kinetic energy = ?
- m = mass of rocket = 0.05 kg
= initial speed = 12 m/s
Therefore,

K.E = 3.6 J
<h3>
b. MAXIMUM GRAVITATIONAL POTENTIAL ENERGY</h3>
First, we will use the third equation of motion to find the maximum height reached by rocket:

where,
- g = -9.81 m/s²
- h = maximum height = ?
- vf = final speed = 0 m/s
Therefore,
2(-9.81 m/s²)h = (0 m/s)² - (12 m/s)²
h = 7.34 m
Hence, the maximum gravitational potential energy will be:
P.E = mgh
P.E = (0.05 kg)(9.81 m/s²)(7.34 m)
P.E = 3.6 J
Learn more about the equations of motion here:
brainly.com/question/5955789
Answer:
energy = 391.902 kJ /mol
Explanation:
given data
wavelength = 305 nm = 305 ×
m
to find out
average energy
solution
we know speed of light is 3 ×
m/s
so we find frequency here first by speed of light formyla
speed = wavelength × frequency
3 ×
= 305 ×
× frequency
frequency = 9.8360 ×
so energy is
energy = hf
here h = 6.62 ×
J-s
so
energy = 6.62 ×
× 9.8360 ×
energy = 6.51 ×
J
so
energy = 6.51 ×
×
kJ/mol
energy = 391.902 kJ /mol
The formula of density is given by
Density = Mass ÷ Volume
We have:
Mass = 1.989 × 10³⁰ kg
Volume =

=

km³
Density =

=1.13×10¹⁸ kg/km³
Converting 1.13 × 10¹⁸ kg/km³ to g/cm³
1.13 × 10¹⁸ kg = 1.13 × 10¹⁸ × 10³ = 1.13 × 10²¹ grams
1 km³ = 1 × 10⁶ cm³
(1.13 × 10²¹) ÷ 10⁶ = 1.13 × 10¹⁵ gr/cm³
Answer: Density 1.13 × 10¹⁵ gr/cm³
Answer:
Gravity and Friction
Explanation:
How gravity and friction work which u probably know