Answer:
4.43 kW
Explanation:
Since Intensity I = P/A = E²/2cμ₀ where P = Power, A = Area = 4πr² where r = distance from source = 61 m and E = electric field amplitude = 8.45 V/m.
P = E²A/2cμ₀ = E²4πr²/2cμ₀ = 2πE²r²/cμ₀
= 2π(8.45 V/m)²(61 m)²/3 × 10⁸ m/s × 4π × 10⁻⁷ Tm/A
= 4428.1 W
= 4.4281 kW ≅ 4.43 kW
Answer:
The final speed of the train car is 8.57 m/s.
Explanation:
Given that,
Mass of train car = 1000 kg
Mass of sand = 400 kg
Speed of train car = 12 m/s
We need to calculate the final speed of the train car after the sand is dumped
Using conservation of momentum
...(I)
Put the value in the equation (I)



Hence, The final speed of the train car is 8.57 m/s.
Answer:
a)
b)
c) Therefore it is a nonconservative force
Explanation:
Distance traveled in one complete circular trip against friction

The force of friction is


The work of friction is the force of friction in the distance so

a).






b).


c).
Since the circle returns to its initial position in both cases and the work done by the friction force different in both cases, so the friction force does depend on the path;
Answer:
Graph 1 matches with B, 2 with A, and 3 with C.
Explanation:
Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.
Answer:
c
Explanation:
neither the spring or hands are in the action of movemnet