Which statement explains the similarity between momentum and kinetic energy of an object?

Physics

1 answer:

Nata [24]2 years ago

7 0

Answer:

B. Both are directly proportional to the mass and velocity of the object.

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polet [3.4K]

Answer:

second option is the answer.

6 0

2 years ago

The _____ of an object is a measure of the distance an object moves in a given amount of time. *

DanielleElmas [232]

Answer:

Option B) Speed is the answer.

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3 years ago

In midair in the international space station a 1 kg chunk of putty moving at 1 m/s collides with and sticks to a 5 kg chunk of p

Delicious77 [7]

<span>We know that the momentum keeps constant in a inelastic collisions, so the product of mass and speed do not change:
m1 * v1 + m2 * v2 = m * v
1 * 1 + 5 * 0 = (1 + 5) * v
1 = 6 * v
v = 1/6 m/s
So the final speed of the 6 kg chunk will travel at 0.167 m/s</span>

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3 years ago

A mass M is hanging from a rope of length L and mass m. A student gives the mass a quick horizontal shake to set up a wave which

disa [49]

Answer:

Explanation:

Expression for velocity of wave produced in a hanging wire can be given as follows

Velocity v = $\sqrt{\frac{T}{m} }$

where T is tension in wire and m is mass of wire per unit length.

In the given case

T = Mg + mg

= Mg

neglecting weight of rope

mass of the rope per unit length

= m / L

Velocity of wave

= $\sqrt{\frac{Mg}{\frac{m}{L} } }$

= $\sqrt{\frac{MgL}{m} }$

4 0

2 years ago

A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast

kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$