<span>The weight lifted by a machine to the applied force on a machine is called mechanical advantage.
This is written as Mechanical advantage, M. A, = load(weight)/effort.
So for 1) M.A = 2 and load = 2, 000lb = 8896.446N.
So 2 = 8896.446/ effort
Effort = 8896.446/2 = 4448.48
Similarly for M.A of 2, 000, 000 we have
Effort = 8896.446/ 2, 000, 000 = 0.004448</span>
I would think b. It equals an equal rate of 2.5 J’s meter
To solve this problem it is necessary to apply the concepts related to the law of Malus.
The light intensity after passing through the first polarizer is given as
Where,
I = Intensity of unpolarized light
The expression for malus law is given as
Where
\theta = Angle between the first and second polarizers
= Intensities of the light after passing through the first and second polarizers respectively.
The intensity of light after passing first polarizer ( Perpendicular to the surface) is
The angle between the first and second polarizers is given by
The expression for Malus law is given by
Therefore the intensity of the light after passing through both the polarizer is
Answer:
Force: Newtons (F = M a = kg * m /s^2)
Acceleration: m / sec^2 (a = meters / sec^2)
Velocity: m / sec (v = meters / sec)
Mass: kg (M = kilograms)
Explanation:
Momentum is conserved in the collision. Momentum is conserved for any interaction between two objects occurring in an isolated system.