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Katarina [22]
3 years ago
13

A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red

light of wavelength 660 nm appear green to him, with a wavelength of 555 nm. The police officer writes out a traffic citation for speeding. How fast was the physicist traveling, according to his own testimony?
Physics
1 answer:
Alik [6]3 years ago
8 0

Answer:

Speed of physicist car is 0.036c or 1.08 x 10⁷ m/s .

Explanation:

Doppler Effect is defined as the change in frequency or wavelength of the wave as the source or/and observer moving away or towards each other.

In this case, the Doppler effect equation in terms of wavelength is :

\lambda_{s} = \lambda_{o}\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }       ......(1)

Here \lambda_{s} is source wavelength, \lambda_{o} is observed wavelength, v is speed of the observer and c is the speed of light.

Given :

Source wavelength, \lambda_{s} = 660 nm = 660 x 10⁻⁹ m

Observed wavelength, \lambda_{0} = 555 nm = 555 x 10⁻⁹ m

Substitute these values in the equation (1).

555\times10^{-9} } = 660\times10^{-9} \sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } }

\sqrt{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = 0.84

{\frac{1-\frac{v}{c} }{1+\frac{v}{c} } } = (0.84)^{2} = 0.7056

1-\frac{v}{c}=0.7056+0.7056\frac{v}{c}

\frac{v}{c}=\frac{0.2944}{8.056}

v = 0.036c=0.036\times3\times10^{8}

v = 1.08 x 10⁷ m/s  

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Complete Question

The two isolated parallel plate capacitors be-  low, one with plate separation d and the other  with D > d, have the same plate area A and

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Answer:

The correct option is 2

Explanation:

The formula for the energy stored in the capacitor is

             U = \frac{Q^2}{2C}

And generally the formula for finding the capacitance of a capacitor is

               C = \frac{\epsilon_oA}{d}

We can denote the capacitance of the first capacitor as C_1 = \frac{\epsilon_oA}{d}

          and   denote the capacitance of the second  capacitor as C_2 = \frac{\epsilon_oA}{D}

Looking at this formula we can see that C varies inversely with d            

as D > d it means that C_1 > C_2

                Since the charge is constant

                         U\  \alpha\ \frac{1}{C} i.e U varies inversely with C

           So C_1 > C_2   => U_2 >U_1

This means that the energy of spark would be more for capacitor two compared to capacitor one

The correct option is 2

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Here,

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