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rosijanka [135]
3 years ago
6

During a rising tide Ocean waves often become larger if the amplitude of a wave increases by a Factor of 1.1, by how much does t

he energy increase
Physics
1 answer:
Alja [10]3 years ago
5 0

Answer:

The energy of the wave will <u>increase by a factor of 1.21</u>.

Explanation:

Given:

The amplitude of the ocean wave is increased by a factor of 1.1.

The energy associated with a wave depends on the amplitude of the wave.

The energy (E) is directly proportional to the square of the amplitude (A) of the wave and is expressed as:

E=kA^2\\Where\ k\to constant\ of\ proportionality

So, if the amplitude is doubled, then the energy will become 4 times and if the amplitude is halved, then the energy reduced by a factor of one by four.

Here, the amplitude is increased by a factor of 1.1. So, the energy associated with it will increase by a factor of square of 1.1 which is given as:

Increase\ in\ Energy=(1.1)^2=1.21\ of\ the\ initial\ value

Therefore, the energy of the wave will increase by a factor of 1.21.

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The period of a wave is the time it takes between two complete oscillations of the wave itself, i.e. it is the time that occurs between two consecutive wavelengths. Therefore, if we want to calculate how many wavelengths pass a certain point in t=2~min=120~s, we need to divide the total time for the period of the wave, T:
N= \frac{t}{T}= \frac{120~s}{15~s}=8
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3 years ago
The first published controlled experiment was designed to
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ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distanc
alexgriva [62]

Answer:

The value is d  =  31.45 \  m

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

v_r  =  v_s  - v_c

substituting 1.05 m/s for v_c and 2.75 m/s for v_s

So

v_r  =  2.75  - 1.05

=> v_r  =  1.7 \  m/s

Generally the distance by which the person is ahead of you is mathematically represented as

d =  v_r  *  t

substituting 18.5 s for t

       d =  1.7  * 18.5

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4 0
3 years ago
A copper wire has a square cross section 2.0 mm on a side. The wire is 5.0 m long and carries a current of 2.0 A. The density of
kondor19780726 [428]

Answer:

30.22 hours

Explanation:

Given data:

A= l² = (2 x 10^{-3})² = 4 x 10^{-6} m²

Length 'L' = 5m

current 'I' = 2 A

density of free electrons 'n'= 8.5 x 10^{28} /m³

Current Density 'J' = I/ A

J= 2/4 x 10^{-6}

J= 5 x 10^{5} A/m²

We can determine the  time required for an electron to travel the length of the wire by

T= L/ Vd

Where,

L is length and Vd is drift velocity.

Vd can be defined by J/ n|q|

where,

n is the charge-carrier number density

|q| is is the charge carried by each charge carrier =>1.6 x 10^{-19}C

T= L/ Vd

Therefore,

T= L . n|q| / J

T= (4 x 8.5 x 10^{28} x |1.6 x 10^{-19}|)/5 x 10^{5}

T= 108800 seconds =>1813.33 minutes

Converting minute into hours:

T= 30.22 hours

Thus, time that is required for an electron to travel the length of the wire is 30.22 hours

4 0
3 years ago
A meter rule balance on a knife headge at the 55cm mark wheb a mass of 40g from 995cm .find the mass of the meter rule.
umka2103 [35]

Answer:

Let the weight of the ruler be X.

Now X acts in the middle, so we have 55-50 = 50cm

Since left hand movement= right hand movement

X(55-50)=90(95-55)

5X= 90×40

X=320cm

Hence the weight of the ruler is 320g

Explanation:

7 0
3 years ago
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