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3 years ago

Going around a ferris wheel without stopping is an example of _____ circular motion(apex)

Physics

2 answers:

Natasha_Volkova [10]3 years ago

5 0

Explanation:

Going around a Ferris wheel without stopping is an example of <u>uniform</u> circular motion. In a circular motion, the objects moves with constant speed but its velocity is continuously changing because of changing direction.

The force acting when the object when it is moving in a circular motion is called centripetal force. The direction of both force and acceleration is inwards.

Hence, "going around a Ferris wheel without stopping" is an example of uniform circular motion.

victus00 [196]3 years ago

3 0

going around a ferris wheel without stopping is an example of uniform circular motion (apex).

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A parallel-plate capacitor with plates of area 600 cm^2 is charged to a potential difference V and is then disconnected from the

Julli [10]

Answer:

Explanation:

a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV

C = capacitance of the capacitor (in Farads )

V = voltage (in volts) = 100V

C = ∈A/d

∈ = permittivity of free space = 8.85 × 10^-12 F/m

A = cross sectional area = 600 cm²

d= distance between the plates = 0.7cm

C = 8.85 × 10^-12 * 600/0.7

C = 7.59*10^-9Farads

Q = 7.59*10^-9 * 100

Q = 7.59*10^-7Coulombs

Q = 0.759*10^-6C

Q = 0.759µC

b) Energy stored in a capacitor is expressed as E = 1/2CV²

E = 1/2 * 7.59*10^-9 * 100²

E = 0.0000395Joules

E = 39.5*10^-6Joules

E = 39.5µJ

7 0

3 years ago

Ask Your Teacher Two long, straight wires are parallel and 11 cm apart. One carries a current of 2.9 A, the other a current of 5

dsp73

Answer:

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is away from one another

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is towards each other.

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi\times 10^{-7}\ N/A^2$

$i_1$ = Current in first wire = 2.9 A

$i_2$ = Current in second wire = 5.3 A

r = Gap between the wires = 11 cm

Force per unit length

$F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N$

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is away from one another

$F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N$

The magnitude of force per unit length of one wire on the other is $2.7945\times 10^{-5}\ N$ and the direction is towards each other.

7 0

2 years ago

A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt

pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light= $\lambda=589nm=589\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.

Change in air film thickness from one edge to other edge is same as the thickness of spacer.

Therefore, thickness of spacer= $2\lambda$

Thickness of spacer= $2\times 589\times 10^{-9}$ m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0

3 years ago

Name two possible ways in wivh fossils can be dated and define them <br>

Vikentia [17]

Answer:

There are two main methods determining a fossils age, relative dating and absolute dating. Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages.

Mark me with a crown

6 0

3 years ago

Read 2 more answers

A ball is thrown upwards. Neglecting air resistance, what initial upward speed does the ball need to remain in the air for a tot

melamori03 [73]

Answer:

H = 1/2 g t^2 time to reach top of trajectory

v = g t time to reach top of trajectory when v is initial speed upwards

v = 5 g = 49 m/s 5 sec upwards and 5 sec downwards

5 0

2 years ago