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faltersainse [42]
4 years ago
11

Going around a ferris wheel without stopping is an example of _____ circular motion(apex)

Physics
2 answers:
Natasha_Volkova [10]4 years ago
5 0

Explanation:

Going around a Ferris wheel without stopping is an example of <u>uniform</u> circular motion. In a circular motion, the objects moves with constant speed but its velocity is continuously changing because of changing direction.

The force acting when the object when it is moving in a circular motion is called centripetal force. The direction of both force and acceleration is inwards.

Hence, "going around a Ferris wheel without stopping" is an example of uniform circular motion.

victus00 [196]4 years ago
3 0

going around a ferris wheel without stopping is an example of uniform circular motion (apex).

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1) The motion of the baseball consists of two separate motions along the horizontal (x) and vertical (y) axis. The position on the two directions at time t is given by:
x(t)=v_0t
y(t)=h- \frac{1}{2}gt^2
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First of all, we can find the time t at which the ball reaches the ground by requiring y(t)=0:
0=h- \frac{1}{2}gt^2
t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2(1.85 m)}{9.81 m/s^2} }=  0.61 s

and if now we substitute this time into the equation for x(t), we find the horizontal distance covered during this time interval, which is the horizontal distance covered by the ball before hitting the ground:
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2) Speed of the ball as it hits the ground
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On the x-axis, the velocity is the same as the initial one: 
v_x=18.1 m/s
On the y-axis, the velocity is given by
v_y(t)=gt
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v_y =gt=(9.81 m/s^2)(0.61 s)=6.0 m/s
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v= \sqrt{v_x^2+v_y^2}= \sqrt{(18.1 m/s)^2+(6.0 m/s)^2}=19.1 m/s
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