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4 years ago

Going around a ferris wheel without stopping is an example of _____ circular motion(apex)

Physics

2 answers:

Natasha_Volkova [10]4 years ago

5 0

Explanation:

Going around a Ferris wheel without stopping is an example of <u>uniform</u> circular motion. In a circular motion, the objects moves with constant speed but its velocity is continuously changing because of changing direction.

The force acting when the object when it is moving in a circular motion is called centripetal force. The direction of both force and acceleration is inwards.

Hence, "going around a Ferris wheel without stopping" is an example of uniform circular motion.

victus00 [196]4 years ago

3 0

going around a ferris wheel without stopping is an example of uniform circular motion (apex).

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If the plates are pulled twice as far apart, but are kept connected to the battery, the electric field between the plates will b

never [62]

Electric field between two parallel plates will be halved as it was before.

What is the electric field between two plates:

The electric field lines of two parallel plates can be represented by straight lines perpendicular to both plates surfaces while carrying arrows that point from +Q plate A toward -Q plate B.

we know that,

The electric field between plates:

E=V / d

where,

V is battery voltage

d is separation distance between plates.

now If the plates are pulled twice as far apart, but are kept connected to the battery,

the separation distance becomes,

d' = 2d

so the new electric field will be:

E' = V / d'

substituting the values,

E' = V / ( 2d )

E' = 1/2 ( V /d )

E' = 1/2 E

hence we can conclude that

Electric field between plates will be halved as it was before.

Learn more about Electric field between plates here:

<u>brainly.com/question/14788793</u>

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2 years ago

The net fedrce on a 12 kg cart is 3.2N backward. Ignoring friction, what is the acceleration

aivan3 [116]

Mass,m = 12 kg

Force,F = 3.2 N

<h3>To be calculated:- </h3>

Calculate the acceleration ( a ) .

<h3>Solution:- </h3>

We know that,

$\bf \: Force = Mass × Acceleration$

$\sf\implies \: 3.2 = 12 \: \times a$

$\sf \implies \: a = \dfrac{3.2}{12}$

$\sf \implies \: a = \dfrac{32}{12 \times 10}$

$\sf \implies \: a \: = \dfrac{8}{3 0}$

$\sf \implies \: a = 0.266$

$\sf \implies \: a = 0.27 \: m {s}^{ - 2} \: (approx)$

6 0

3 years ago

Read 2 more answers

The electric current is a

Kipish [7]

AC current .........,............

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3 years ago

What is electromagnetic induction?

Hoochie [10]

Answer:

Magnetic induction is the production of an electromotive force (voltage).

4 0

3 years ago

A 3.1 kg dog stands on an 18 kg flatboat and is 6.1 m from the shore. He walks 2.5 m on the boat toward shore and then stops. As

Pachacha [2.7K]

Answer:

The distance of dog from the shore is 3.97 m

Explanation:

given,

mass of the dog = 3.1 Kg

mass of the flatboat = 18 Kg

Distance from the shore = 6.1 m

dog moves on boat = 2.5 m

dog moves leftward and boat moves rightward.

If it's a frictionless system with no initial velocity, the center of mass doesn't move. Conservation of momentum, which = 0 in this case.

When dog move toward the shore a reactive force will act on the boat.

$m_b x_b + m_d x_d = 0$

m_b i and m_d is mass of boat and mass of dog.

x_b and x_d is distance moved by the boat and the dog.

$x_b = \dfrac{m_dx_d}{m_b}$

neglecting negative sign

x_b + x_d = 2.5

$\dfrac{m_dx_d}{m_b} + x_d = 2.5$

$x_d = \dfrac{2.5}{1+\dfrac{m_d}{m_b}}$

$x_d = \dfrac{2.5}{1+\dfrac{3.1}{18}}$

$x_d = \dfrac{2.5}{1.172}$

x_d = 2.133 m

The distance of dog from the shore is 6.1 – 2.133 = 3.97 m

The distance of dog from the shore is 3.97 m

4 0

3 years ago