Answer:
The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking.
The amount of calories contained in the food we eat every day must represent the amount of calories eliminated by the body in that time to have a steady weight.
Explanation:
The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking. If total quantity of calories in the food we consume every day is higher that the average number of calories needed daily, then weight increases by fat accumulation.
Life darling
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Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B534%5Ctimes%28%20485g%29%5Ctimes%28%2010%5E3mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%20%5Ctimes%20%28100in%5E2%29%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=37.4mpy
mm/yr
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B87.6%5Ctimes%20%28485g%29%5Ctimes%20%2810%5E3%20mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%5Ctimes%20%28100in%5E2%29%5Ctimes%282.54cm%2Fin%29%5E2%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Light energy is defined as how nature moves energy at an extremely rapid rate, and it makes up about 99% of the body's atoms and cells, and signal all body parts to carry out their respective tasks. An example of light energy is the movement of a radio signal.
To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution. By definition is defined as:
![\theta = 1.22\frac{\lambda}{d}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.22%5Cfrac%7B%5Clambda%7D%7Bd%7D)
Where,
= Wavelength
d = Width of the slit
= Angular resolution
Through the arc length we can find the radius, which would be given according to the length and angle previously described.
The radius of the beam on the moon is
![r = l\theta](https://tex.z-dn.net/?f=r%20%3D%20l%5Ctheta)
Relacing ![\theta](https://tex.z-dn.net/?f=%5Ctheta)
![r = l(\frac{1.22\lambda}{d})](https://tex.z-dn.net/?f=r%20%3D%20l%28%5Cfrac%7B1.22%5Clambda%7D%7Bd%7D%29)
![r = 1.22\frac{l\lambda}{d}](https://tex.z-dn.net/?f=r%20%3D%201.22%5Cfrac%7Bl%5Clambda%7D%7Bd%7D)
Replacing with our values we have that,
![r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})](https://tex.z-dn.net/?f=r%20%3D%201.22%2A%28%5Cfrac%7B%28384%2A10%5E3km%29%28%5Cfrac%7B1000m%7D%7B1km%7D%29%28550%2A10%5E%7B-9%7Dm%29%7D%7B7%2A10%5E%7B%7B-2%7D%7D%7D%29)
![r = 3680.91m](https://tex.z-dn.net/?f=r%20%3D%203680.91m)
Therefore the diameter of the beam on the moon is
![d = 2r](https://tex.z-dn.net/?f=d%20%3D%202r)
![d = 2 * (3690.91)](https://tex.z-dn.net/?f=d%20%3D%202%20%2A%20%283690.91%29)
![d = 7361.8285m](https://tex.z-dn.net/?f=d%20%3D%207361.8285m)
Hence, the diameter of the beam when it reaches the moon is 7361.82m