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mestny [16]
3 years ago
5

A quantity of a gas has an absolute pressure of 400kPa and an absolute temperature of 110 degrees Kelvin. When the temperature o

f the gas is raised to 235 degrees Kelvin, what's the new pressure of the gas?
Physics
1 answer:
Jet001 [13]3 years ago
6 0

Intially, we have:

Pressure P1 = 400KPa

Temperature T1= 110Kelvin

When,

Temperature T2= 235 Kelvin

Pressure P2= ?

We have gas equation:

PV= nRT

P/T= nR/V

Considering nR/T as constant, we have:

P1/T1 = P2/T2

400/110= P2/235

P2= 854.5 KPa

So the new temperature will be 854.5 KPa


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False you dont repaint your hamster.

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What is the weight of a dog with a mass of 12 kg? Explain how you obtained your answer.
butalik [34]

Answer: 117.60N

Explanation:

Weight is a force. Therefore, we can use the force formula to find weight.

Formula: W=m*g

W = weight

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5 0
3 years ago
Read 2 more answers
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

  • ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
  • ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

5 0
3 years ago
Use the general formulas for gravitational force and centripetal force to derive the relationship between speed (v) and orbital
german

Solution :

We know that :

Formula for Gravitational force is given by :

$F_g=\frac{Gmn}{r^2}$

where, G is the gravitational constant

            M is the mass of the bigger body

            m is the mass of the smaller body

            r  is the distance between the two bodies.

And the formula for the centripetal force is given by :

$F_c=\frac{mv^2}{r}$

where, m is the mass of the rotating body

            v is the velocity

             r is the radius of rotation of the body.

We know that mathematically, the gravitational force is equal to the centripetal force of the body.

Therefore,

$F_g=F_c$

$\frac{GMm}{r^2}=\frac{mv^2}{r}$

$\sqrt{\frac{GM}{r}}=v$

Hence derived.

5 0
3 years ago
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