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IceJOKER [234]
3 years ago
14

A car speedometer that is supposed to read the linear speed of the car uses a device that actually measures the angular speed of

the tires. if larger-diameter tires are mounted on the car instead, how will that affect the speedometer reading? the speedometer
Physics
1 answer:
nikklg [1K]3 years ago
4 0
When a car<span> rounds a corner at a constant </span>speed<span>, its acceleration is zero. Suppose you are in a </span>car<span> that is going around a curve. The speedometer reads a constant 30 miles per hour. ... </span>Describe the speed<span> of the object from 4-6 seconds using the distance vs. time graph.</span>
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Name a device that converts mechanical energy into electrical energy.
erma4kov [3.2K]

Answer:

Electric generator is the device that converts mechanical energy into electrical energy

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3 years ago
When pressing the accelerator on a car, the _______ energy of the fuel is transformed into the ______ energy that makes the car
Oksanka [162]
- Chemical
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Where does solar energy wastes go
ryzh [129]

Answer:

Space

Explanation:

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3 0
2 years ago
Calculate the angular velocity of a clocks second hand, its minute hand, and its hour hand. State in Rad/s. What is its angular
fenix001 [56]

Second hand:

1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec

Minute hand:

1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec

Hour hand:

1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec

As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.

8 0
3 years ago
Derive a general formula for projectile motion with the object launched at an angle
vagabundo [1.1K]

Answer:

  y = x tan θ - (g / 2v₀² cos² θ) x²

Explanation:

An equation is called a general formula that relates the position on the x-axis and the height on the body's axis.

Let's write the position on each axis

X axis. No acceleration

         x = v₀ₓ t

Y Axis.  There is the acceleration of gravity

        y = v_{oy} t - ½ g t²

Let's clear the time in the first equation and substitute in the second

       y = v₀ sin θ  (x / v₀ₓ) - ½ g (x / v₀ₓ)²

       y = v₀ sin θ / v₀ cos θ x - ½ g x² / v₀² cos² θ

       y = x tan θ - (g / 2v₀² cos² θ) x²

This is the trajectory equation in projectile launching

6 0
3 years ago
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