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sukhopar [10]
3 years ago
15

Write the expression as a single logarithm

Mathematics
1 answer:
vredina [299]3 years ago
4 0

3\log_7y + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - \log_7z^{5})\\\log_7y^{3} + 4(\log_7(\frac{x}{z^{5}}))\\\log_7y^{3} + \log_7(\frac{x}{z^{5}})^{4}\\\log_7(y^{3} \times (\frac{x}{z^5{5}})^{4})

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c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and  Studied for the Midterm = 75

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Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

N=(25+60)+(40+60) - 60\\N= 125

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