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sukhopar [10]
3 years ago
15

Write the expression as a single logarithm

Mathematics
1 answer:
vredina [299]3 years ago
4 0

3\log_7y + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - \log_7z^{5})\\\log_7y^{3} + 4(\log_7(\frac{x}{z^{5}}))\\\log_7y^{3} + \log_7(\frac{x}{z^{5}})^{4}\\\log_7(y^{3} \times (\frac{x}{z^5{5}})^{4})

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This is a homeork problem from my class
rosijanka [135]
This is a quadratic function:

f(x)=ax²+bx+c

We have three points:
(0 , 77.6)     
(5 ,  78)
(10 , 78.6)

Then, we make the function wiht these points:
(0 , 77.6)

x=0
f(x)=77.6

a(0)²+b(0)+c=77.6
c=77.6

(5 , 78)
a(5)²+b(5)+77.6=78
25a+5b=78-77.6
25a+5b=0.4         (1)

(10 , 78.6)
a(10)²+b(10)+77.6=78.6
100a+10b=78.6-77.6
100a+10b=1        (2)

With the equations (1) and (2) we have a system of equations:
100a+10b=1
  25a + 5b=0.4

We solve this system of equations by method of elimination.

   100a+10b=1
-4(25a+5b=0.4)
-----------------------------
           -10b=-0.6      ⇒    b=-0.6/-10=0.06

   100a+10b=1
-2(25a+5b=0.4)
----------------------------
     50a =  0.2          ⇒ a=0.2/50=0.004

We have a, b and c:
a=0.004
b=0.06
c=77.6

Therefore, the quadratic funtion is:
f(x)=0.004x²+0.06x+77.6
x=year of the beginning of the interval - 1980

The life expectancy for females born between 1995 and 2000 is when x=1995-1980=15
Therefore:
f(15)=0.004(15)²+0.06(15)+77.6
f(15)=0.004(225)+0.06(15)+77.6
f(15)=79.4

The life expectancy for females born between 2000 and 2005 is when:
x=2000-1980=20
therefore:
f(20)=0.004(20)²+0.06(20)+77.6
f(20)=1.6+1.2+77.6
f(20)=80.4

Answer:
The funtion is:
f(x)=0.004x²+0.06x+77.6
x=year of the beginning of the interval - 1980

The life expectancy for females born between 1995 and 2000 is 79.4 years.
The life expectancy for females born between 2000 and 2005 is 80.4 years.

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Any of these?? i need help with this packet
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The answer to number 1 is 14
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3(x+10)=2(2x+16) help please & thank you
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In this question, you have to isolate <em>x</em>.

First, use the distributive property.

3x+30=4x+32

Now that you have distributed, subtract the constants. 


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