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Dimas [21]
4 years ago
12

HELP ME IN CHEMISTRY PLEASE

Chemistry
1 answer:
Hoochie [10]4 years ago
6 0
The answer is the first one because the sodium is the first element of the third row, thus 3s^1
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What is the smallest part of an element that still retains properties of that element?
Leni [432]
The smallest part is the atom
4 0
3 years ago
Read 2 more answers
Acetic acid, ethanol, acetaldehyde and ethane form a series of 2-carbon molecules which differ in their extent of oxidation. Con
yanalaym [24]
<h2>CH_3CH_2OH  →  CH_3CHO </h2>

Explanation:

Ethanol can be oxidized to ethanal or acetaldehyde which is further oxidized to acid that is acetic acid.

CH_3CH_2OH→  CH_3CHO [oxidation by loss of hydrogen]

  • An oxidizing agent potassium dichromate(VI) solution is used to remove the hydrogen from the ethanol.  
  • An oxidizing agent used along with dilute sulphuric acid for acidification.

Acetaldehyde can also be reduced back to ethanol again by adding hydrogen to it by using a reducing agent that is sodium tetrahydro borate, NaBH4.

  • The oxidation of aldehydes to carboxylic acids can be done by the two-step process.  
  • In the first step, one molecule of water is added in the presence of a catalyst that is acidic.
  • There is a generation of a hydrate. (geminal 1,1-diol).

     CH_3CHO  →  CH_3CH_2COOH [reduction by the gain of electrons]

Here, the oxidizing agent used isCr_3O in the presence of acetone.

7 0
3 years ago
Look at the diagram of an electrolytic cell below.
Ipatiy [6.2K]

<em>The cathode is Y</em>

<h3><em>Further explanation</em></h3>

Electrolysis uses electrical energy to carry out redox reactions that are not spontaneous.

The ions in the solution flowing electrically will move towards to opposite charge of the electrode

The electrolysis material is an electrolyte which can be a solution or a melt.

In positive pole electrolysis cells - the anode is the site of the oxidation reaction, while the negative pole - the cathode is the reduction reaction site.

The result of the reaction in the anode is based on a substance that easily oxidized while the reaction in the cathode is based on a substance that easily reduced.

Electrons (electricity) enter an electrolysis cell through the negative pole (cathode)

The negative ion from the solution will move towards the positive electrode and release the electrons around the positive electrode (oxidation) and the electrons flow to the negative pole

Whereas around the negative electrode, there is electron binding and a reduction reaction occurs

So if we see the picture the cathode is Y

<h3><em>Learn more</em></h3><h3><em>reaction related to electrochemistry brainly.com/question/3461108</em></h3>

<h3><em>Answer details </em></h3>

Grade: Senior High School

Subject: Chemistry

Chapter: Electrochemistry

Keywords: cathode, anode, oxidation, reduction, negative pole, electrode

8 0
4 years ago
Which discovery is most directly related to careers in biology?
Nookie1986 [14]
Molecular and Microbiology 
5 0
4 years ago
Two voltaic cells are to be joined so that one will run the other as an electrolytic cell. In the first cell, one half-cell has
vladimir1956 [14]

Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell.

<h3>What is an electrolytic cell?</h3>

An electrolytic cell that uses electrical energy to enable a non-spontaneous redox reaction is known as an electrolytic cell.

Certain chemicals can be electrolyzed using electrolytic cells, which are electrochemical cells.

For example, water can be electrolyzed to create gaseous oxygen and gaseous hydrogen with the use of an electrolytic cell.

The following are the three essential parts of electrolytic cells:

Cathode (which is negatively charged for electrolytic cells)

Anode (which is positively charged for electrolytic cells)

Electrolyte

The reactions for each half cell is given by

Au^{3+}(aq) + 3e^- \rightleftharpoons Au(s) ; E° = 1.50 V

Cr^{3+}(aq) + 3e^- \rightleftharpoons Cr(s) ; E° = –0.74 V

Co^{2+}(aq) + 2e^- \rightleftharpoons Co(s) ; E° = –0.28 V

Zn^{2+}(aq) + 2e^- \rightleftharpoons Zn(s) ; E° = –0.76 V

When the Au/Cr cell will run as a voltaic cell and Co/Zn cell will run as an electrolytic cell, the a difference in the voltages is produced

E^o_{series} = E^o_{Au/Cr} - E^o_{Co/Zn}  = 2.24 V – 0.48 V = 1.76 V

Learn more about electrolytic cell:

brainly.com/question/19854746

#SPJ4

7 0
1 year ago
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